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(curlV)ndoover the part of the surfacez=9x29y2 above the (x,y)plane, if .V=2xyi+(x22x)jx2z2k

Short Answer

Expert verified

The solution is(curlV)nd=6

Step by step solution

01

Given Information.

The given equation isV=2xyi+(x22x)jx2z2k

02

Definition of vector.

A quantity that has magnitude as well as direction is called a vector. It is typically denoted by an arrow in which the head determines the direction of the vector and the length determines its magnitude.

03

Apply Stokes’ theorem.

Calculate the expression (肠耻谤濒痴)脳苍诲蟽forV=2xyi+(x22x)jx2z2k over the surface z=9x29y2above the x-yplane(i.e., for z0).This surface is bounded by the ellipse9x29y2=0 which means that, using Stokes's theorem, the original integral can be calculated over any surface enclosed by this ellipse, which is taken to be the surface on the x-yplane (i.e., the ellipse itself). The curlVof is derived as shown below.

curlV=VzyVyzi+VxzVzxj+VyxVxyk

=(00)i+02xz2j+(2x22x)k

=-2K

Therefore, the integral of -2Kover the area of an ellipse is x29+y2=1.

Its normal vector is and its area is which gives the solution shown below.

(curlV)苍诲蟽=(2)k办诲蟽

=-2(3)

=-6

Hence, the solution is (curlV)nd=6.

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