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Do Problem 3 in spherical coordinates; compare the results with Problem 8.3.

Short Answer

Expert verified

Answer

The components of accelerations are mentioned below.

ar=r¨-r˙θ2-r˙ϕ2sin2θaθ=r¨+2˙θ˙θ-r˙ϕ2sinθcosθaϕ=rsinθ˙ϕ+2sinθ˙r˙ϕ+2rcosθ˙θ˙ϕ..

Step by step solution

01

Given Information

The motion of as particle acted on by force isF=∇V..

02

Definition of spherical coordinates.

The coordinate system primarily utilized in three-dimensional systems is the spherical coordinates of the system. The spherical coordinate system is used to find the surface area in three-dimensional space.

03

Find the value.

Formula for the Lagrange of the system in cylindrical coordinates is mentioned below.

L=12mr˙2-Vr,ϕ,zL=re∧r¨+r˙ϕθ-r˙ϕ2e∧ϕ+r˙ϕe∧zL=12mr2+r2ϕ2+z˙2-Vr,ϕ,z

Apply Euler Lagrange’s on the equation mentioned above

ddt∂L∂r=m¨r=mr˙θ2+mrsin2θ˙ϕ2-∂V∂rddt∂L∂r=mr2¨θ=2mr˙θ˙=mr2sinθ˙ϕ2-∂V∂rddt∂L∂ϕ=mrddtr2sin2θϕ=-∂V∂ϕ

Divide the equation with respective scale factors given below.

hϕ=rhr=1hz=1

The equation becomes as follows.

mr-r˙θ2-rsin2θϕ2=-∂V∂rmr¨θ+2r˙θ-rsinθϕ2=-1r∂V∂θmrsinθϕ¨+2sinθr˙ϕ+2rcosθ˙θ˙ϕ=-1rsinθ∂V∂ϕ

The components of acceleration are mentioned below.

ar=r¨-r˙θ2-r˙ϕ2θaθ=r¨θ+2˙θ˙θ-r˙ϕ2sinθcosθaϕ=rsinθ¨ϕ+2sinθr˙ϕ˙+2rcosθ˙θ˙ϕ

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