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Do Problem 5 for the coordinate systems indicated in Problems 10 to 13. Parabolic.

Short Answer

Expert verified

The required values are mentioned below.

∇U=1u2+v2∂U∂ue^u+1u2+v2∂U∂ve^v+1uv∂U∂ϕe^ϕ∇.V=1(u2+v2)uv∂∂uu2+v2uvV1+1(u2+v2)uv∂∂uu2+v2uvV2)+1uv∂V3∂ϕ∇2U=1(u2+v2)uv∂∂uuv∂U∂u+1u2+v2uv∂∂vuv∂U∂u+1u2v2∂2U∂ϕ∇×V=1uvu2+v2∂∂v(uvV3)-∂∂ϕu2+v2V2e^u+1uvu2+v2∂∂ϕu2+v2V1)-∂∂uuvV3e^v+1u2+v2∂∂uu2+v2V2-∂∂vu2+v2V1e^ϕ

Step by step solution

01

Given Information

The Parabolic.

02

Definition of cylindrical coordinates.

The coordinate system primarily utilized in three-dimensional systems is the cylindrical coordinates of the system. The cylindrical coordinate system is used to find the surface area in three-dimensional space.

03

Determining the value of ∇U, ∇.V , ∇2U and ∇×Vand  

The scale factors are given below.

hu=u2+v2hv=u2+v2hϕ=uv

Find∇Uin Parabolic coordinates.

∇U=1hu∂U∂ue^u+1hu∂U∂ve^v+1hu∂U∂ϕe^ϕ∇U=1u2+v2∂U∂ue^u+1u2+v2∂U∂ue^v+1uv∂U∂ϕe^ϕ

Find the divergence of V.

∇.V=1(u2+v2)uv∂∂uu2+v2uvV1+∂∂vu2+v2uvV2+∂∂ϕ(u2+v2)V3∇.V=1(u2+v2)uv∂∂uu2+v2uvV1+1(u2+v2)uv∂∂uu2+v2uvV2)+1uv∂V3∂ϕ

Find the Laplacian of U.

∇2U=1(u2+v2)uv∂∂uuv∂U∂u+1u2+v2uv∂∂vuv∂U∂u+1u2v2∂2U∂ϕ∇2U=1(u2+v2)uv∂∂uuv∂U∂u+1u2+v2uv∂∂vuv∂U∂u+1u2v2∂2U∂ϕ

Find curl of V.

∇×V=1uvu2+v2∂∂v(uvV3)-∂∂ϕu2+v2V2e^u+1uvu2+v2∂∂ϕu2+v2V1)-∂∂uuvV3e^v+1u2+v2∂∂uu2+v2V2-∂∂vu2+v2V1e^ϕ

Hence, the required values are mentioned below.

role="math" localid="1659339435729" ∇U=1u2+v2∂U∂ue^u+1u2+v2∂U∂ve^v+1uv∂U∂ϕe^ϕ∇.V=1(u2+v2)uv∂∂uu2+v2uvV1+1(u2+v2)uv∂∂uu2+v2uvV2)+1uv∂V3∂ϕ∇2U=1(u2+v2)uv∂∂uuv∂U∂u+1u2+v2uv∂∂vuv∂U∂u+1u2v2∂2U∂ϕ∇×V=1uvu2+v2∂∂v(uvV3)-∂∂ϕu2+v2V2e^u+1uvu2+v2∂∂ϕu2+v2V1)-∂∂uuvV3e^v+1u2+v2∂∂uu2+v2V2-∂∂vu2+v2V1e^ϕ

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