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Use L23of the Laplace Transform Table (page 469 ) to evaluate ∫0∞tJ0(2t)e^-tdt.

Short Answer

Expert verified

The equation by use of Laplace theorem is ∫0∞(tJ0)(2t)e-1dt=5.

Step by step solution

01

Concept of Laplace Transform

The Laplace transform is an integral transform in mathematics that turns a function of a real variable (typically time) to a function of a complex variable. It is named after its inventor Pierre-Simon Laplace. (Complex periodicity)

02

Determine equations with proof:

The given equation is as follow.

∫0∞tJ0(2t)e-1dt ….. (1)

Let g(t)=(tJ0)-(2t)

Therefore,

∫0∞tJ0(2t)e-1dt=L(g(t))

Thus,

L(g(t))=LtJ0(2t)=-ddpL1P2+4=pP2+4

At p = 1

L(g(t))=1×12+4=5

Hence, the solution is role="math" localid="1659263208798" ∫0∞(tJ0)(2t)e-1dt=5.

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