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To show the following equation shown in the problem

2ddxJa(x)=Ja-1(x).

Short Answer

Expert verified

The answer is,2ddxJa(x)=Ja-1(x) .

Step by step solution

01

 Step 1: Concept of Bessel Function:

The Bessel functions of the first kindJn(x) are defined as the solutions to the Bessel differential equation.

x2d2ydx2+xdydx+(x2-n2)y=0

02

Solve the equation 2ddxJa(x)=Ja-1(x)-Ja+1(x)  about the Bessel Function:

The given equation for the following equation is shown as,

2ddxJa(x)=Ja-1(x)-Ja+1(x)

By the use of the following proposition about the zeros of Bessel functions solve the equation as follows:

ddxJ(x)=ddxxa(x-J(x))=x-1Jx+xddxxJx=-x-1Jax+x-xJ-1x=-x-1Jx+Ja-1x
03

Calculation of the equation ddx(xαx-αJα(x) :

By adding the two expressions as follows:

ddxJa(x)=ddxxx-Jx=x-1Jx+xddxxJ(x)=J-1(x)-J+1x/22ddxJ(x)=Ja-1x-Ja+1(x)

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