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Use the Section 15 recursion relations and (17.4) to obtain the following recursion relations for spherical Bessel functions. We have written them for jn, but they are valid for ynand for the hn

(ddx)jn(x)=jn-1(x)-(n+1)jn(x)/x

Short Answer

Expert verified

The resultant answer is(ddx)(jn(x))=-n+1xjn(x)+jn-1(x)

Step by step solution

01

Concept of Spherical Bessel functions:

The spherical Bessel function is given as follows:

hn(1)(x)=jn(x)+iyn(x)

With:


jn(x)+xn(-1xddx)n(sin(x)x)yn(x)=-xn(-1xddx)n(cos(x)x)Formulaused:jn(x)=∑r-0∞(-1)rΓ(r+1)Γ(r+1+n)(x2)2r+n

02

Calculate the equation by the Spherical Bessel function:

Using the Spherical Bessel function to obtain:

ddxjnx=ddxπ2xJn+12x=πx-12x-32Jn+12x+x-32Jn+12x=π2x-12xJn+12x+2n+12xjn+12x-Jn+32xJpx=2pxJpx-Jp+1xSimplifyfurtherasfollows:ddxjnx=π2x2n2xJn+12+1x=nxjnx-jn+1xTherefore,ddxjnx=nxjnx-jn+1x.

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Most popular questions from this chapter

Expand each of the following polynomials in a Legendre series. You should get the same results that you got by a different method in the corresponding problems in Section 5.

x-x3

Expand the following functions in Legendre series.

f(x)=arcsinx

Expand the following functions in Legendre series.


Solve the following eigenvalue problem (see end of Section 2 and problem 11): Given the differential equation y''+(λx−14−l(l+1)x2)y=0where l is an integerlocalid="1654860659044" ≥0 , find values of localid="1654860714122" λsuch that localid="1654860676211" y→0 aslocalid="1654860742759" role="math" x→∞ , and find the corresponding eigenfunctions. Hint: letlocalid="1654860764612" y=xl+1e−x/2v(x), and show that localid="1654860784518" v(x) satisfies the differential equationlocalid="1654860800910" xv''+(2l+2−x)v'+(λ−l−1)v=0.Comparelocalid="1654860829619" (22.26) to show that if localid="1654860854431" λ is an integerlocalid="1654860871428" >l, there is a polynomial solution localid="1654860888067" v(x)=Lλ−t−12t+1(x).Solve the eigenvalue problem localid="1654860910472" y''+(λx−14−l(l+1)x2)y=0.

Prove the least squares approximation property of Legendre polynomials [see (9.5) and (9.6)] as follows. Let f(x) be the given function to be approximated. Let the functions pl(x)be the normalized Legendre polynomials, that is, pl(x) = √(2l+1)/2 Pl(x) , so that

∫-11[pl(x)"]"2dx=1.

Show thatLegendre series for f(x)as far as the p2(x)term is

f(x)=c0p0(x)+c1p1(x) +c3p3(x) with c1 =∫-11f(x)pl(x) dx

Write the quadratic polynomial satisfying the least squares condition as b0p0(x)+b1p1(x)+b0p0(x)by Problem 5.14 any quadratic polynomial can be written in this form). The problem is to find b0, b1, b2so that I=∫-11[f2(x)+(b0-c0)2+(b1-c1)2+(b2-c2)2 -c02 -c12 -c22] dx

Now determine the values of the b's to make I as small as possible. (Hint: The smallest value the square of a real number can have is zero.) Generalize the proof to polynomials of degree n.

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