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A random variable x takes the values with probabilities 512,13,112,16.

Short Answer

Expert verified

The required values are mentioned below.

μ=1var(x)=76σ=76

Step by step solution

01

Given Information

A random variable x.

02

Definition of the cumulative distribution function

The likelihood that a comparable continuous random variable has a value less than or equal to the function's argument is the value of the function.

03

Find the values

The mean is given below.

μ=∑0×5pxiμ=0×512+1×13+2×112+3×16μ=1

The variance is given below.

var(x)=∑xi−μ2pxivar(x)=0-12×512+1-12×13+×112+3-12×16var(x)=76

The standard deviation is given below.

σ=var(x)σ=76

Thegraph is shown below.

Hence, the required values are mentioned below.

μ=1var(x)=76σ=76

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