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If,z=x2+2y2,x=rcosθ,y=rsinθ, find the following partial derivatives.

∂2z∂r∂y

Short Answer

Expert verified

The value of provided equation is ∂2z∂r∂y=0.

Step by step solution

01

Given data

The given data are listed below

z=x2+2y2....(1)x=rcosθ.....(2)y=rsinθ......(3)

02

Partial differentiation

The procedure of calculating the partial derivative of a function is called partial differentiation. This method is used to get the partial derivative of a function with respect to one variable while keeping the other constant.

03

Calculation

From equation 1 and 2,

z=rcosθ2+2y2z=r2cos2θ+2y2

Take the partial derivative of z with respect to r,

∂z∂r=∂∂r(r2cos2θ+2y2)∂z∂r=2rcos2θ

Take the partial derivative of ∂z∂rwith respect to y,

∂2z∂z∂y=∂2∂z∂y2rcos2θ∂2z∂z∂y=0

Hence,∂2z∂z∂y=0

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