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Write the Schr枚dinger equation (3.22) if is a function ofx, and V=12m2x2 (this is a one-dimensional harmonic oscillator). Find the solutions n(x)and the energy eigenvalues En . Hints: In Chapter 12, equation (22.1) and the first equation in (22.11), replace xby xwhere =m/. (Don't forget appropriate factors of for the x' 's in the denominators of D=ddxand ''=d2dx2.) Compare your results for equation (22.1) with the Schr枚dinger equation you wrote above to see that they are identical if En=(n+12). Write the solutions n(x)of the Schr枚dinger equation using Chapter 12, equations (22.11) and (22.12).

Short Answer

Expert verified

The solution is:

yn(x)=n(x)=(mDmx)nem2x2

Step by step solution

01

Given Information:

The Hermite Differential equation is given:

yn''x2yn=(2n+1)yn

02

 Definition of Schrödinger equation:

A linear partial differential equation that governs the wave function of a quantum-mechanical system is known as Schr枚dinger equation.

03

Use the Hermite differential equation:

Rewrite Hermite differential equation in the form of one dimensional harmonic oscillator.

Replace xbyx.

Here,=m.

The modified linear operator is:

D=ddxD'=mD

Use the modified linear Differential Operator to rewrite the Hermit Differential Equation.

(D'+mx)yn=(mD+sqrtmx)yn=(myn'+mxyn)

(D'mx)(myn'+mxyn)=(mDmx)(myn'+mxyn)=myn''mx2yn+yn

04

Step 4:Generate the Schrödinger equation:

For a one-dimensional harmonic oscillator, generate the Schr枚dinger equation.

myn''mx2yn+yn=2nyn22myn''+12m2x2yn2yn=nyn22myn''+12m2x2yn=2yn+nyn22myn''+12m2x2yn=(n+12)yn

Hence the solution is:

yn(x)=n(x)=(mDmx)nem2x2

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