/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q26P Use L28 and L4 to find the inver... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Use L28 and L4 to find the inverse transform ofpe-ptI(p2+1).

Short Answer

Expert verified

Answer

The inverse Laplace transforms of is

L-1p-ezp2+1=ft=cost-Ï€,0,t>Ï€t<Ï€

Step by step solution

01

Given information

The given function is pe-p2Ip2+1

02

Definition of Laplace Transformation

A transformation of a function f(x) into the function g(t) that is useful especially in reducing the solution of an ordinary linear differential equation with constant coefficients to the solution of a polynomial equation.

The inverse Laplace transform of a function F(s) is the piecewise-continuous and exponentially-restricted real function f(t)

03

Inverse Transformation of the given function

From(L28)

Lft=gt-a,0,t>00=e-pwGp

From L4

Lcosf=pw2+a2

From above equation

Lcost=pp2+1

By use of L28;

Lft=gt-a,0,t>a>00=e-puGp

And consider the

L-1e-pxGp=ft=gt-a,0,t>a>00L-1pxp2+1=ft=gt-Ï€,0,t>Ï€t<Ï€

Thus, the inverse Laplace transforms of p×rp2+1isL-1p-ezp2+1=ft=cost-π,0,t>πt<π.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.