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Write equations (10.6) to (10.9) in matrix form as discussed just after (10.9).

Short Answer

Expert verified

Inner product of Aand B=∑i=1nAi*Bi

Norm of A=A=∑i=1nAi*Ai

A and Bare orthogonal =∑i=1nAi*Bi=0

Schwarz inequality =∑i=1nAi*Bi⩽∑i=1nAi*Ai∑i=1nBi*Bi

Inner product of Aand B=a11a12.a1na21a22.a2n....an1an2.ann.b11b12.b1nb21b22.b2n....bn1bn2.bnn

Norm of A= deta11a12.a1na21a22.a2n....an1an2.ann=a11a22.a2n...a2n.ann+a12a21.a2n...an1.ann+......+a1na21a22....an1an2.

A and B are orthogonal, a11a12.a1na21a22.a2n....an1an2.ann.b11b12.b1nb21b22.b2n....bn1bn2.bnn=0

Schwarz inequality =∑i=1nAi*Bi⩽∑i=1nAi*Ai∑i=1nBi*Bi

Step by step solution

01

Given information from question

Inner product:

An inner product is a generalization of the dot product. In a vector space, it is a way to multiply vectors together, with the result of this multiplication being a scalar.


More precisely, for a real vector space, an inner product ⟨·,·⟩satisfies the following four properties. Let u,vand wbe vectors and abe a scalar, then:

1. ⟨u+v,w⟩=⟨u,w⟩+⟨v,w⟩

2. ⟨αv,w⟩=α⟨v,w⟩

3. ⟨v,w⟩=⟨w,v⟩

4. ⟨v,v⟩⩾0and equal if and only if v=0

Norm: A norm is a function from a real or complex vector space to the non-negative real numbers that exhibits some characteristics similar to the angle to the origin, including scaling, a form of the triangle inequality, and being zero exclusively at the origin.


Norm of A=A=∑i=1nAi*Ai

Aand Bare orthogonal =∑i=1nAi*Bi=0

Schwarz inequality =∑i=1nAi*Bi⩽∑i=1nAi*Ai∑i=1nBi*Bi

Inner product of Aand B=a11a12.a1na21a22.a2n....an1an2.ann.b11b12.b1nb21b22.b2n....bn1bn2.bnn

Norm of A = deta11a12.a1na21a22.a2n....an1an2.ann=a11a22.a2n...an2.ann+a12a21.a2n...an1.ann+.......+a1na21a22....an1an2.

A and B are orthogonal , a11a12.a1na21a22.a2n....an1an2.ann.b11b12.b1nb21b22.b2n....bn1bn2.bnn=0

Schwarz inequality =∑i=1nAi*Bi⩽∑i=1nAi*Ai∑i=1nBi*Bi

deta11a12.a1na21a22.a2n....an1an2.ann.b11b12.b1nb21b22.b2n....bn1bn2.bnn≤

deta11a12.a1na21a22.a2n....an1an2.ann.detb11b12.b1nb21b22.b2n....bn1bn2.bnn

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