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For given sets of basis vectors, use the Gram-Schmidt method to find an orthonormal set.

(a)A=(0,2,0,0),B=(3,-4,0,0),C=(1,2,3,4)

(b)A=(0,0,0,7),B=(2,0,0,5),C=(3,1,1,4)

(c)A=(6,0,0,0),B=(1,0,2,0),C=(4,1,9,2)

Short Answer

Expert verified

(a) The orthonormal set is e1,e2,e3=0,1,0,0,1,0,0,0,0,0,3,45

(b)The orthonormal set is e1,e2,e3=0,0,0,1,1,0,0,0,0,1,1,02

(c) The orthonormal set ise1,e2,e3=1,0,0,0,0,0,1,0,0,1,0,25

Step by step solution

01

(a) Find the orthonormal set

The given set of basis vectors is

A=0,2,0,0,B=3,-4,0,0,C=1,2,3,4

First, normalize the first vector as follows:

e1=AA=0,2,0,022=0,2,0,02=0,1,0,0

Now, projecting vector Bon the first basis and subtracting this component of vector Bas follows:

B-Be1e1=3,-4,0,0--40,1,0,0=3,-4,0,0-0,-4,0,0=3,0,0,0

Let鈥檚 normalize this vector and let it be e2.

e2=3,0,0,032=3,0,0,03=1,0,0,0

Next, for vector C, project it on e1and e2, and subtracting those components from C.

C-Ce1e1-Ce2e2=1,2,3,4-20,1,0,0-11,0,0,0=1,2,3,4-0,2,0,0-1,0,0,0=0,0,3,4

Now, normalizing the above vector, then the vector e3 is:

e3=0,0,3,432+42=0,0,3,49+16=0,0,3,425=0,0,3,45

Hence, the orthonormal set ise1,e2,e3=0,1,0,0,1,0,0,0,0,0,3,45

02

(b) Find the orthonormal set

The given set of basis vectors is

A=0,0,0,7,B=2,0,0,5,C=3,1,1,4

First, normalize the first vector as follows:

e1=AA=0,0,0,772=0,0,0,77=0,0,0,1

Now, projecting vector Bon the first basis and subtracting this component of vector B.

B-Be1e1=2,0,0,5-50,0,0,1=2,0,0,5-0,0,0,5=2,0,0,0

Le鈥 normalize this vector and let it be e2.

e2=2,0,0,022=2,0,0,02=1,0,0,0

Next, for vector C, project it on e1and e2, and subtracting those components from Cas follows:

C-Ce1e1-Ce2e2=3,1,1,4-40,0,0,1-31,0,0,0=3,1,1,4-0,0,0,4-3,0,0,0=0,1,1,0

Now, normalizing the above vector, then the vector e3 is:

e3=0,1,1,012+12=0,1,1,01+1=0,1,1,02

Hence, the orthonormal set ise1,e2,e3=0,0,0,1,1,0,0,0,0,1,1,02

03

(c) Find the orthonormal set

The given set of basis vectors is

A=6,0,0,0,B=1,0,2,0,C=4,1,9,2

First, normalize the first vector as follows:

e1=AA=6,0,0,062=6,0,0,06=1,0,0,0

Now, projecting vector Bon the first basis and subtracting this component of vector B.

B-Be1e1=1,0,2,0-11,0,0,0=1,0,2,0-1,0,0,0=0,0,2,0

Let鈥檚 normalize this vector and let it be e2.

e2=0,0,2,022=0,0,2,02=0,0,1,0

Next, for vector C, project it on e1and e2, and subtracting those components from Cgives:

C-Ce1e1-Ce2e2=4,1,9,2-41,0,0,0-90,0,1,0=4,1,9,2-4,0,0,0-0,0,9,0=0,1,0,2

Now, normalizing the above vector, the vector e3is:

e3=0,1,0,212+22=0,1,0,21+4=0,1,0,25

Hence, the orthonormal set is e1,e2,e3=1,0,0,0,0,0,1,0,0,1,0,25

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