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In(6.14), let θ=ϕ=ττ/2 and verify the result numerically.

Short Answer

Expert verified

The relation cosϕ-sinϕsinϕcosϕcosθ-sinθsinθcosθ=cos(θ+ϕ)-sin(θ+ϕ)sin(θ+ϕ)cos(θ+ϕ)is verified numerically for and its numerical value is -100-1.

Step by step solution

01

The trigonometric values of sine and cosine function for different angles:

The numerical values of the sine and cosine function at π2, and πare

sin(Ï€2)=1cos(Ï€2)=0sin(Ï€)=0cos(Ï€)=-1

02

Given parameters:

The result (6.14) is cosϕ-sinϕsinϕcosϕcosθ-sinθsinθcosθ=cos(θ+ϕ)-sin(θ+ϕ)sin(θ+ϕ)cos(θ+ϕ).

It needs to be verified for θ=ϕ=π/2.

03

Finding the numerical values of the left-hand side and the right-hand side of the relation:

Substitute into the left-hand side of the relation (6.14)and evaluate the result.

cosπ2-sinπ2sinπ2cosπ2cosπ2-sinπ2sinπ2cosπ2=0-1100-110

Multiply the matrices.

cosπ2-sinπ2sinπ2cosπ2cosπ2-sinπ2sinπ2cosπ2=-100-1

Substitute θ=ϕ=π/2into the right-hand side of the relation (6.14).

role="math" localid="1658989214239" cosπ2+π2-sinπ2+π2sinπ2+π2cosπ2+π2=cosπ-sin(π)sin(π)cos(π)

Evaluate the sine and cosine function.

cosπ-sin(π)sin(π)cos(π)=-100-1

Hence, the relation (6.14) is verified numerically

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