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Use the ratio test to find whether the following series converge or diverge:

23.∑n=1∞n!100n

Short Answer

Expert verified

The series ∑n=1∞n!100ndivergence.

Step by step solution

01

Process of ratio test

Apply ratio test in the given series by usingÒÏn=|an+1an|andÒÏ=limn→∞ÒÏn, wherean+1 is the(n+1)th term of the series andan is thenth term. If ÒÏ<1, then the series converges. If ÒÏ>1, then the series diverges.

02

Apply the ratio test

The given series is ∑n=1∞n!100n.

So, an+1=n+1!100n+1, role="math" an=n!100n.

Obtain the value of ÒÏn=an+1an.

ÒÏn=an+1an=n+1!100n+1÷n!100n=n+1!100n+1×100nn!=n+1100

03

Solve the limit

Now,ÒÏlimn→∞ÒÏn is calculated as follows:

ÒÏ=limn→∞n+1100=∞100=∞

Here, ÒÏ>1, therefore the series diverges.

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