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Use the ratio test to find whether the following series converge or diverge:

22.∑n=1∞10n(n!)2

Short Answer

Expert verified

The series∑n=1∞10nn!2 is convergent.

Step by step solution

01

Process of ratio test

Apply ratio test in the given series by usingÒÏn=|an+1an|andÒÏ=limn→∞ÒÏn, wherean+1 is the(n+1)th term of the series andan is thenth term. If role="math" ÒÏ<1, then the series converges. If role="math" ÒÏ>1, then the series diverges.

02

Apply the ratio test

The given series is∑n=1∞10nn!2.

So, an+1=10n+1n+1!2, and localid="1664185894811" an=10nn!2.

Obtain the value of ÒÏn=an+1an.

ÒÏn=an+1an=10n+1n+1!2÷10nn!2=10n+1n+1!2×n!210n=10n+12

03

Solve the limit

Now,ÒÏ=limn→∞ÒÏn is calculated as follows:

role="math" localid="1664186203147" ÒÏ=limn→∞10n+12=10∞+12=10∞=0

Here ÒÏ<1, therefore the series converges.

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