/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q11P Question: Show that the Maclauri... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Question: Show that the Maclaurin series for sin x converges to sin x . Hint: If f (x)= sinf(n+1)(X)=±sinxor±cosx, and so f(n+1)(x)≤1

for all x and all n. Letn→∞in (14.2).

Short Answer

Expert verified

Hence prove, Maclaurin Series for sin x converges to sin x .

Step by step solution

01

Define Maclaurin Series

Maclaurin series is basically a type of power series expansion of the function about the origin, with all the terms having positive values expanded as:f(x)=f(0)+xf'(0)+x22f"(0)+.......+x2nf(n)(0)+..........

02

Determine the proof for the Macular-in series

The given function is f(x)=sin x

Now, the formula for the remainder is given by:

Rn(x)=xn+1f(n+1)(c)(n+1)

Consider the equation f(n+1)(x)=±sinxor±cosxwith f(n+1)(x)≤1

So, we taking limit of remainder as follow:

limn→∞Rn(x)=limn→∞xn+1(n+1) = 0

Clearly, the remainder is zero, this implies that the series will converges to itself.

Hence prove, Maclaurin Series for sin x converges to sin x .

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Find a two-term approximation for each of the following integrals and an error bound for the given t interval ∫0tXe-xdx,0<t<0.01

(a) Using computer or tables (or see Chapter 7,Section 11),verify that∑n=1∞(1/n2)=π26=1.6449=,and also verify that the error in approximating the sum of the series by the first five terms is approximately 0.1813.

(b) By computer or tables verify that ∑n=1∞(1/n2)(1/2)n=π212-(1/2)(ln2)2=0.5815+

the sum of the first five terms is0.5815+

(c) Prove theorem (14.4). Hint: The error is |∑N+1∞anxn|.

Use the fact that the absolute value of a sum is less than or equal to the sum of the absolute values. Then use the fact that |an+1|≤|an|to replace all anby aN+1 , and write the appropriate inequality. Sum the geometric series to get the result.

Solve for all possible values of the real numbers xand y in the following equations.x+iy=(1-i)2

In the following problems, find the limit of the given sequence asn→∞

The velocityof electrons from a high energy accelerator is very near the velocityof light. Given the voltage Vof the accelerator, we often want to calculate the ratio v / c. The relativistic formula for this calculation is (approximately, forV≫1)

vc=1-(0.511V)2, V=Number of million volts

Use two terms of the binomial series (13.5) to find1 - v/cin terms ofV. Use your result to find 1 - v/cfor the following values of V. Caution: V= the number of millionvolts.

(a) V =100 million volts

(b)V =500 million volts

(c)V =25,000 million volts

(d)V =100 gigavolts (100109 volts105 million volts)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.