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91Ó°ÊÓ

Reduce the equation

x2d2ydx2+2xdydx-5y=0

to a differential equation with constant coefficients in d2ydz2,dydz, and y by the change of variable x=ex. (See Chapter 8, Section 7d.)

Short Answer

Expert verified

Hence, the required differential equation is d2ydz2+dydz-5y=0.

Step by step solution

01

Higher order derivatives

If any function fx has its derivative with respect to x that is f'x, then further differentiation of f'x with respect to x results higher order derivative of fx.

02

Differentiate the given equation

The given equation is:

x2d2ydx2+2xdydx-5y=0

Now, we havex=ez⇒dxdz=ez⇒dzdx=e-z. Then,

dydx=dydz×dzdx=e-zdydz

And,

d2ydx2=ddxe-zdydz=ddze-zdydzdzdx=e-zd2ydz2-e-zdydze-z=e-2zd2ydz2-dydzx2d2ydx2=d2ydz2-dydz

03

Solve the obtained derivatives

Substitute all these values in x2d2ydx2+2xdydx-5y=0, and we get:

x2d2ydx2+2xdydx-5y=0d2ydz2-dydz+2dydx-5y=0d2ydz2+dydz-5y=0

Hence, the required differential equation is d2ydz2+dydz-5y=0.

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