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In each case, show that a particle whose coordinate is (a) x=Rez, (b)y=Imzis undergoing simple harmonic motion, and find the amplitude, period, frequency, and velocity amplitude of the motion.

z=2e-it/2

Short Answer

Expert verified

The velocity amplitude is = 1.

Period =4Ï€

Frequency=14Ï€

Amplitude = 2

Step by step solution

01

Given data

The given complex function isz=f(t)and z=2e-it/2.

02

Concept of Periodic motion formula

Time Period (T): The length of time it takes for a motion to repeat itself. Thus, a time period is measured in seconds.

Frequency (f): It is determined by counting how many times a motion is repeated in a second. Hz is the symbol for frequency (Hertz).

Frequency is related to Time period as f=1T.

03

Calculation for the real function

Following is the complex function:

z=f(t)z=2cost2+isint2

Consider a particle whose coordinate is Re(z).

Now, Re(z)=2cost2.

By definition an object is executing simple harmonic motion if its displacement from equilibrium can be written as:

AsinÓ¬t[Orrole="math" localid="1659240088045" AcosÓ¬torAsinÓ¬t-Ï• or AcosÓ¬t-Ï•]

Hence, this particle is undergoing simple harmonic motion.

04

Calculation for the velocity amplitude

Now, for coordinate, Re(z)=2cost2.

Amplitude = 2

Ó¬=1/2

For period:

Period =2Ï€Ó¬

For frequency:

Frequency =1period

Frequency =14Ï€

Period =4Ï€

Velocity amplitude=AÓ¬

Velocity amplitude = 1

05

Calculation for the imaginary function

Following is the complex function:

z=f(t)z=2cost2+isint2

Consider a particle whose coordinate is lm(z).

Now, lmz=2sint2.

By definition an object is executing simple harmonic motion if its displacement from equilibrium can be written as:

AsinÓ¬t[OrAcosÓ¬t orAsinÓ¬t-Ï• orAcosÓ¬t-Ï•]

Hence, this particle is undergoing simple harmonic motion.

06

Calculation for the velocity amplitude

Now, for coordinate, lmz=2sint2.

Amplitude = 2

Ó¬=1/2

For period:

Period =2Ï€Ó¬

Period=4Ï€

For frequency:

Frequency =1period

Frequency =14Ï€

Velocity amplitude =AÓ¬

Velocity amplitude = 1

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