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91Ó°ÊÓ

Sketch several periods of the corresponding periodic function of period 2Ï€ . Expand the periodic function in a sine-cosine Fourier series.

f(x)={-1,-Ï€<x<Ï€21,Ï€2<x<Ï€,

Short Answer

Expert verified

The answer of the given function is:

f(x)=14+1π∑n=1+4∞cosnxn-∑n=3+4∞cosnxn+2π-2∑n=2+4m∞sinnxn+2∑n=1+2m∞sinnxnwherem=0,1,2,--.

Step by step solution

01

Given

The given function is f(x)={-1,-Ï€<x<Ï€21,Ï€2<x<Ï€,.

02

The concept of the Fourier series for the function f(x)

The Fourier series for the function :

f(x)=a02+∑n=1∞(ancosnx+bnsinnx)a0=1π∫-ππf(x)dxan=1π∫-ππf(x)cosnxdxbn=1π∫-ππf(x)sinnxdx

If is an even function:

bn=0f(x)=a02+∑n=1∞ancosnx

If is an odd function:

a0=aa=0f(x)=∑n=1∞bnsinnx

03

From the given information

The sketch of the given function is shown below.

Coefficients of a0:

a0=1π∫-ππf(x)dx=1π-∫-ππ2dx+∫π2πdx=1πxππ2+xπ2π=-1

Coefficients of an:

an=1π∫-ππf(x)cosnxdx=1π∫-ππ2cosnxdx+∫π2Ï€cosnxdx=1Ï€sinnxππ2+sinnxÏ€2Ï€=2²ÔÏ€sinnÏ€2

04

Calculate Coefficients of  bn

Coefficients of bn are 1Ï€,22Ï€,13Ï€,0,15Ï€,26Ï€,17Ï€.

Hence the expansion is f(x)=12+2π∑n=1+4∞cosnxn-∑n=3+4∞cosnxn+2π-2∑n=2+4m∞sinnxn+2∑n=1+2m∞sinnxnwhere m=0,1,2,--..

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