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In each of the following problems you are given a function on the interval -π<x<π .Sketch several periods of the corresponding periodic function of period 2ττ . Expand the periodic function in a sine-cosine Fourier series,

f(x)={-x,-Ï€<x<0x,0<x<Ï€

Short Answer

Expert verified

The resultant expansion is fx=π2+4π∑k=2n+1∞coskxk2n=0,1,2,3,.....

Step by step solution

01

Given data

The given function isfx=Ï€+x,-Ï€<x<0Ï€-x,0<x<Ï€. .

02

Concept of Fourier series

An infinite sum of sines and cosines is used to represent the expansion of a periodic function f(x) into a Fourier series.

The orthogonality relationships of the sine and cosine functions are used in Fourier series.

03

Sketch the points

The sketch for the function is shown below.

04

 Step 4: Find the coefficients of the series

The function is even, so Bn=0.

The rest of the coefficients are given below.

A0=2π∫0ππ-xdx=2ππ³æ-12x20Ï€A0=Ï€A0=2π∫0ππ-xcosnx

Calculate further as follows:

=2ππnsinnx-xnsinnx-1n2cosnx0Ï€An=-2Ï€²Ô2-1n-1=4Ï€°ì2

Where k=2n+1 and n=0,1,2,3,.....

Thus, the function is fx=π2+4π∑k=2n+1∞coskxk2n=0,1,2,3,....

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