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Find the disk on convergence for each of the following complex power series.

∑n=1∞2n(z+i-3)2n

Short Answer

Expert verified

The region of convergent is z-3+i<12.

Step by step solution

01

Given data

The given series is, ∑n=1∞2n(z+i-3)2n.

02

Concept of Ration test

The ratio test is a check (or "criterion") to see if a series will eventually converge to ∑n-1∞an. Every term is a real or complex number, and when n is big, is not zero.

03

Calculation to check the series is convergent

Find An andAn+1 as follows:

An=2nz-3+i2nAn+1=2n+1z-3+i2n+2

Apply ratio test as follows:

ÒÏ=limn→∞An+1AnÒÏ=limn→∞2n+1z-3+i2n+22nz-3+i2nÒÏ=2z-3+i2

If, ÒÏ<1, then the series is convergence.

04

Calculation to find the region of convergent

The region of convergence is given as follows:

2z-3+i2<1z-3+i2<12z-3+i<12

Let, z=x+iy

Therefore, calculate further as follows:

x+iy-3+i<12x-3+y+1i<12x-32+y+12<12x-32+y+12<12

It is an equation of disk with center 3,-1 andr=12.

Hence, the region of convergent is z-3+i<12.

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