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Test each of the following series for convergence.

∑(3+2i)nn!

Short Answer

Expert verified

The series converges, i.e., ÒÏ<1.

Step by step solution

01

Given Information.

The given series, i.e.,∑(3+2i)nn!

02

Definition of Convergent and Divergent series.

A convergent series is one in which the partial sums all gravitate to the same finite number, also known as a limit. Divergent refers to any series that is not converging.

03

Calculate the value of ρn .

Find the value of anand an+1

role="math" localid="1658730311852" an=3+2inn!...(1)an=3+2in+1n+1!...(2)

If ÒÏ<1series converges, if ÒÏ>1then diverges.

ÒÏ=limn→∞ÒÏn

04

Test the series for convergence.

Use the ratio test and put n+1!=n+1n!

ÒÏn=an+1an=3+2in+1(n+1)!×n!3+2inÒÏn=3+2in+13+2in×n!(n+1)n!=3+2in+1

Calculate the value of ÒÏ, i.e.,

ÒÏ=limn→∞3+2in+1=3+2i∞=0

Hence, the series converges, i.e., ÒÏ<1.

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