/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q14P Use Fermat鈥檚 principle to find... [FREE SOLUTION] | 91影视

91影视

Use Fermat鈥檚 principle to find the path followed by a light ray if the index of refraction is proportional to the given function

14.r-1

Short Answer

Expert verified

r=aeb, where a=eBC1-C2and b=C1-C2, where C is a constant andB is the integration constant.

Step by step solution

01

Given Information.

The given function isr-1.Path followed by light is to be found out using Euler equations.

02

Definition of Euler equation

The Euler equations are a set of second-order ordinary differential equations that are stationary points of the given action functional in the calculus of variations and classical mechanics.

03

Use Euler equation

To find the path traversed by light in a given medium, the path taken by the light is to be minimized (time wise). Velocity of light is scaled by a factor n1in a refractive medium, then the time required to travel from point A to point B is

t=ABdt=ABvds=c1ABnds

Therefore, following integral needs to be minimized

nds=ndr2+r22=n1+r2'2dr

Here n=r1

Therefore F=r11+r2'2is to be minimized

Euler equation for coordinates r,is ddrF'-F=0

Calculate the required derivatives

F'=r2'r1+r2'2F=0

Therefore,

ddrr2'r1+r2'2=0r2'r1+r2'2=C'2=C2r21-C2'=Cr1-C2

Where Cis constant.

Integrate '=Cr1-C2to get the desired result

=Cr1-C2dr=C1-C2drr=C1-C2Inr+B

Move Bto the left side, multiply by constants to isolate rand take the exponential of the whole expression to get

eC1-C2-B=r

Takea=eBC1-C2and b=C1-C2to get

r=aeb

It corresponds to two-dimensional spiral

Therefore, r=aeb, where a=eBC1-C2and b=C1-C2, where C is a constant and Bis the integration constant.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In Problems 5 to 7, use Fermat鈥檚 principle to find the path followed by a light ray if the index of refraction is proportional to the given function.

(2x+5)12.

Two particles each of mass m are connected by an (inextensible) string of length I. One particle moves on a horizontal table (assume no friction), The string passes through a hole in the table and the particle at the lower end moves up and down along a vertical line. Find the Lagrange equations of motion of the particles. Hint: Let the coordinates of the particle on the table be r and , and let the coordinate of the other particle be z. Eliminate one variable from L(usingr+z=I)and write two Lagrange equations.

Use Fermat鈥檚 principle to find the path followed by a light ray if the index of refraction is proportional to the given function

12. y-1

Write the胃Lagrange equation for a particle moving in a plane ifV=V(r) (that

is, a central force). Use theequation to show that:

(a) The angular momentum rmvis constant.

(b) The vector r sweeps out equal areas in equal times (Kepler鈥檚 second law).

Show that the actual path is not necessarily one of minimum time. Hint: In the diagram, A is a source of light; CD is a cross section of a reflecting surface, and B is a point to which a light ray is to be reflected. APB is to be the actual path and AP'B, AP"B represent varied paths. Then show that the varied paths:

(a) Are the same length as the actual path if CD is an ellipse with A and B as foci.

(b) Are longer than the actual path if CD is a line tangent at P to the ellipse in (a).

(c) Are shorter than the actual path if CD is an arc of a curve tangent to the ellipse at P and lying inside it. Note that in this case the time is a maximum!

(d) Are longer on one side and shorter on the other if CD crosses the ellipse at P but is tangent to it (that is, CD has a point of inflection at P).

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.