Chapter 2: Problem 24
The magnetic vector potential for a uniformly charged rotating spherical shell is $$ \mathbf{A}=\left\\{\begin{array}{ll} \hat{\varphi} \frac{\mu_{0} a^{4} \sigma \omega}{3} \cdot \frac{\sin \theta}{r^{2}}, & r>a \\ \hat{\varphi} \frac{\mu_{0} a \sigma \omega}{3} \cdot r \cos \theta, & ra \\ B_{\theta}(r, \theta) &=\frac{\mu_{0} a^{4} \sigma \omega}{3} \cdot \frac{\sin \theta}{r^{3}}, & & r>a \\ B &=\hat{z} \frac{2 \mu_{0} a \sigma \omega}{3}, & & r
Short Answer
Step by step solution
Understand the given vector potential
Recall and apply the curl of \( \mathbf{A} \) in spherical coordinates
Calculate \( \mathbf{B} \) for \( r > a \)
Calculate \( \mathbf{B} \) for \( r < a \)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Magnetic Vector Potential
In this context, we are looking at a rotating spherical shell with uniform surface charge density. The vector potential for such a structure is determined based on the region inside and outside the sphere. For \( r > a \), \( \mathbf{A} = \hat{\varphi} \frac{\mu_{0} a^{4} \sigma \omega}{3} \cdot \frac{\sin \theta}{r^{2}} \), and for \( r < a \), it's \( \mathbf{A} = \hat{\varphi} \frac{\mu_{0} a \sigma \omega}{3} \cdot r \cos \theta \). These expressions account for how the charge distribution and rotation influence the magnetic effects outside and inside the shell, respectively.
Spherical Coordinates
- \( r \) is the distance from the origin to the point.- \( \theta \) is the angle between the positive \( z \)-axis and the line formed by \( r \).- \( \varphi \) is the angle from the positive \( x \)-axis to the projection of the radius onto the \( xy \)-plane.These coordinates are particularly useful for problems involving spheres, as they naturally allow us to express positions on the surface of a sphere or distances relative to the center. In our example, the spherical shell's behavior is very naturally described using these coordinates, especially when calculating fields and potentials.
Curl of a Vector
In spherical coordinates, calculating the curl can be complex due to the dependence on \( r \), \( \theta \), and \( \varphi \). The expression for the curl involves terms like \( \frac{1}{r \sin \theta} \left[ \frac{\partial}{\partial \theta}(\sin \theta A_\varphi) \right] \) and \( -\frac{1}{r \sin \theta} \left[ \frac{\partial}{\partial r}(r A_\varphi) \right] \). In our particular problem, since \( A_r = 0 \) and \( A_\theta = 0 \), the expression simplifies somewhat, focusing mainly on terms involving \( A_\varphi \). Calculating this helps us find the magnitude and direction of the magnetic field corresponding to the vector potential.
Charged Rotating Spherical Shell
- **Characteristics:** - The radius of the shell is \( a \). - It has a surface charge density \( \sigma \). - It rotates with angular velocity \( \omega \).The analysis of the magnetic fields produced by this shell revolves around using the above parameters along with the magnetic vector potential \( \mathbf{A} \). For the region outside the shell \( (r > a) \), the field behaves differently compared to the region inside \( (r < a) \), due to the nature of how the charges are distributed and move. Understanding this behavior helps in solving many practical problems involving rotation and symmetry in electromagnetism.