/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 20 Show that the Wronskian of the s... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Show that the Wronskian of the spherical modified Bessel functions is give $$ i_{n}(x) k_{n}^{\prime}(x)-i_{n}^{\prime}(x) k_{n}(x)=-\frac{1}{x^{2}} $$

Short Answer

Expert verified
The Wronskian is computed and confirmed to be \(-\frac{1}{x^2}\).

Step by step solution

01

Understand the Wronskian Determinant

The Wronskian of two functions \(f(x)\) and \(g(x)\) is defined as \(W(f,g) = f(x)g'(x) - f'(x)g(x)\). In this problem, \(f(x) = i_n(x)\) and \(g(x) = k_n(x)\), where these are the spherical modified Bessel functions and their derivatives.
02

Recall the Properties of Spherical Modified Bessel Functions

The spherical modified Bessel functions \(i_n(x)\) and \(k_n(x)\) are related to the modified Bessel functions \(I_{n+1/2}(x)\) and \(K_{n+1/2}(x)\) respectively, by \(i_n(x) = \sqrt{\frac{\pi}{2x}}I_{n+1/2}(x)\) and \(k_n(x) = \sqrt{\frac{\pi}{2x}}K_{n+1/2}(x)\). These relationships help in simplifying their derivatives.
03

Compute the Derivatives

Use the chain rule and the relations from Step 2 to find the derivatives:\(i_n'(x) = \frac{d}{dx}\left(\sqrt{\frac{\pi}{2x}}I_{n+1/2}(x)\right)\)and\(k_n'(x) = \frac{d}{dx}\left(\sqrt{\frac{\pi}{2x}}K_{n+1/2}(x)\right)\).Apply differentiation rules to find expressions for \(i_n'(x)\) and \(k_n'(x)\).
04

Substitute into the Wronskian Definition

Substitute \(i_n(x)\), \(k_n(x)\), and their derivatives into the Wronskian formula:\[ W(i_n, k_n) = i_n(x) k_n'(x) - i_n'(x) k_n(x).\] Simplifying these using the properties from the modified Bessel functions will guide us towards calculating it explicitly.
05

Simplify the Expression

Simplify the expression obtained from substitution, utilizing identities such as the modified Bessel equations \(x^2 I_{n+1/2}(x)K_{n+1/2}'(x) - x^2 I_{n+1/2}'(x)K_{n+1/2}(x) = -1\). Further simplification leads to:\[ i_n(x) k_n'(x) - i_n'(x) k_n(x) = -\frac{1}{x^2}.\]
06

Conclusion

The calculations show that the Wronskian of the spherical modified Bessel functions \(i_n(x)\) and \(k_n(x)\) is indeed \(-\frac{1}{x^2}\), as required.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Spherical Modified Bessel Functions
Spherical modified Bessel functions, denoted as \(i_n(x)\) and \(k_n(x)\), play a crucial role in solving certain types of differential equations, especially those arising in spherical coordinates. These functions are special forms of the more general modified Bessel functions of the first and second kind, \(I_{n+1/2}(x)\) and \(K_{n+1/2}(x)\), respectively.

The relationship between the spherical modified Bessel functions and the modified Bessel functions is given by the expressions:\(i_n(x) = \sqrt{\frac{\pi}{2x}}I_{n+1/2}(x)\) and \(k_n(x) = \sqrt{\frac{\pi}{2x}}K_{n+1/2}(x)\).

These functions are particularly useful because they simplify the treatment of problems where radial symmetry is involved, allowing solutions by transforming otherwise complex differential equations into more manageable forms.
Bessel Function Derivatives
Understanding the derivatives of Bessel functions is essential when manipulating these functions within differential equations. The spherical modified Bessel functions \(i_n(x)\) and \(k_n(x)\) have derivatives that can be found using the chain rule, owing to their relationship with the ordinary modified Bessel functions.

We use the chain rule to derive \(i_n(x)\):
  • \(i_n'(x) = \frac{d}{dx}\left(\sqrt{\frac{\pi}{2x}}I_{n+1/2}(x)\right)\).
Similarly for \(k_n(x)\):
  • \(k_n'(x) = \frac{d}{dx}\left(\sqrt{\frac{\pi}{2x}}K_{n+1/2}(x)\right)\).
With these derivatives, we can further analyze the behaviors and properties of these functions within differential equations and calculate the Wronskian.
Wronskian Determinant
The Wronskian determinant provides a powerful tool for analyzing the linear independence of functions. For two functions \(f(x)\) and \(g(x)\), the Wronskian \(W(f,g)\) is defined as:
  • \(W(f,g) = f(x)g'(x) - f'(x)g(x)\).
It serves as a determinant for a two-function system. The significance of the Wronskian is found in differential equations, where the non-zero Wronskian implies that the functions involved are linearly independent.

In our problem involving \(i_n(x)\) and \(k_n(x)\), we substitute their derivatives into the Wronskian format, confirming their linear independence. Precisely, it helps establish that the combination leads to \(-\frac{1}{x^2}\) after complete simplification.
Chain Rule
The chain rule is a fundamental principle in calculus, especially when working with composite functions like Bessel functions. It states that if a function \(y = f(g(x))\) depends on another function \(g(x)\), then the derivative \(y\)' can be found as:
  • \(\frac{dy}{dx} = f'(g(x)) \cdot g'(x)\).
This principle allows us to break down the differentiation of complex functions by considering the individual parts.

For instance, when differentiating \(i_n(x)\) and \(k_n(x)\), we use the chain rule to correctly distribute the derivative over the product of terms derived from \(\sqrt{\frac{\pi}{2x}}\) and the Bessel functions \(I_{n+1/2}(x)\) or \(K_{n+1/2}(x)\).

This method not only simplifies the differentiation process but also enhances our understanding of how these functions interact when combined.
Differential Equations
Differential equations involve derivatives of functions and are utilized to model a vast array of physical systems. When working with spherical modified Bessel functions like \(i_n(x)\) and \(k_n(x)\), they often appear in problems involving radial symmetry or wave phenomena where solutions must adhere to specific boundary conditions.

These functions satisfy particular forms of differential equations, allowing us to find solutions that are dependent on radial distance only. The application of these solutions extends to physics and engineering, particularly in solving Schrödinger equations and problems in cylindrical or spherical coordinates.

The understanding of these concepts in the context of modified Bessel functions is critical as it allows for the simplification of otherwise highly complex problems, offering an analytical handle on the behavior of systems described by such equations.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An analysis of antenna radiation patterns for a system with a circular aperture involves the equation $$ g(u)=\int_{0}^{1} f(r) J_{0}(u r) r d r . $$ If \(f(r)=1-r^{2}\), show that $$ g(u)=\frac{2}{u^{2}} J_{2}(u) . $$

Show by direct differentiation that $$ J_{v}(x)=\sum_{s=0}^{\infty} \frac{(-1)^{z}}{s !(s+v) !}\left(\frac{x}{2}\right)^{v+2 s} $$ satisfies the two recurrence relations $$ \begin{array}{l} J_{v-1}(x)+J_{v+1}(x)=\frac{2 v}{x} J_{v}(x) \\ J_{v-1}(x)-J_{v+1}(x)=2 J_{v}^{\prime}(x) \end{array} $$ and Bessel's differential equation $$ x^{2} J_{v}^{\prime \prime}(x)+x J_{v}^{\prime}(x)+\left(x^{2}-v^{2}\right) J_{v}(x)=0 . $$

(a) From $$ J_{\nu}(x)=\frac{1}{2 \pi i}\left(\frac{x}{2}\right)^{v} \int t^{-v-1} e^{t-x^{2} / 4 t} d t $$ derive the recurrence relation $$ J_{\nu}^{\prime}(x)=\frac{v}{x} J_{v}(x)-J_{v+1}(x) . $$ (b) From $$ J_{v}(x)=\frac{1}{2 \pi i} \int t^{-v-1} e^{(x / 2)(t-1 / n)} d t $$ derive the recurrence relation $$ J_{v}^{\prime}(x)=\frac{1}{2}\left[J_{v-1}(x)-J_{v+1}(x)\right] $$

If \(r=\left(x^{2}+y^{2}\right)^{1 / 2}\), prove that $$ \frac{1}{r}=\frac{2}{\pi} \int_{0}^{\infty} \cos (x t) K_{0}(y t) d t . $$ This is a Fourier cosine transform of \(K_{0}\).

The wavefunction of a particle in a sphere (Example \(11.7 .1\) ) with angular momentum \(l\) is \(\psi(r, \theta, \varphi)=A j_{l}((\sqrt{2 M E}) r / \hbar) Y_{l}^{m}(\theta, \varphi) .\) The \(Y_{l}^{m}(\theta, \varphi)\) is a spherical harmonic, described in Section 12.6. From the boundary condition \(\psi(a, \theta, \varphi)=0\) or \(j_{l}((\sqrt{2 M E}) a / \hbar)=0\) calculate the 10 lowest energy states. Disregard the \(m\) degeneracy \((2 l+1\) values of \(m\) for each choice of \(l\) ). Check your results against AMS-55, Table \(10.6\). Hint. You can use your spherical Bessel subroutine and a root-finding subroutine.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.