/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 5 Given the three vectors. $$ ... [FREE SOLUTION] | 91Ó°ÊÓ

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Given the three vectors. $$ \begin{array}{l} \mathbf{P}=3 \hat{\mathbf{x}}+2 \hat{\mathbf{y}}-\mathbf{z} \\ \mathbf{Q}=-6 \hat{\mathbf{x}}-4 \hat{\mathbf{y}}+2 \mathbf{2}, \\ \mathbf{R}=\hat{\mathbf{x}}-2 \hat{\mathbf{y}}-\mathbf{z} \end{array} $$ find two that are perpendicular and two that are parallel or antiparallel.

Short Answer

Expert verified
Vectors \( \mathbf{P} \) and \( \mathbf{R} \) are perpendicular; \( \mathbf{Q} \) and \( \mathbf{P} \) are antiparallel.

Step by step solution

01

Define the Condition for Perpendicular Vectors

Two vectors are perpendicular if their dot product is zero. For vectors \( \mathbf{A} = a_1 \hat{x} + a_2 \hat{y} + a_3 \hat{z} \) and \( \mathbf{B} = b_1 \hat{x} + b_2 \hat{y} + b_3 \hat{z} \), the dot product is \( \mathbf{A} \cdot \mathbf{B} = a_1b_1 + a_2b_2 + a_3b_3 \). If this equals zero, then \( \mathbf{A} \) and \( \mathbf{B} \) are perpendicular.
02

Find Perpendicular Vectors

Calculate the dot product for each pair of vectors. For \( \mathbf{P} \cdot \mathbf{Q} \): \( (3)(-6) + (2)(-4) + (-1)(2) = -18 - 8 - 2 = -28 \) (not zero).For \( \mathbf{P} \cdot \mathbf{R} \): \( (3)(1) + (2)(-2) + (-1)(-1) = 3 - 4 + 1 = 0 \), so \( \mathbf{P} \) and \( \mathbf{R} \) are perpendicular.For \( \mathbf{Q} \cdot \mathbf{R} \): \( (-6)(1) + (-4)(-2) + (2)(-1) = -6 + 8 - 2 = 0 \), so \( \mathbf{Q} \) and \( \mathbf{R} \) are also perpendicular.
03

Define the Condition for Parallel or Antiparallel Vectors

Two vectors are parallel or antiparallel if one is a scalar multiple of the other. If \( \mathbf{A} = k \mathbf{B} \) where \( k \) is a non-zero scalar, the vectors are parallel if \( k > 0 \) and antiparallel if \( k < 0 \).
04

Check for Parallel or Antiparallel Vectors

Compare the coefficients of \( \mathbf{P}, \mathbf{Q}, \mathbf{R} \) to find a scalar multiple relation:\( \mathbf{Q} = -2 \mathbf{P} \) since \( -2 \times 3 = -6 \), \( -2 \times 2 = -4 \), and \( -2 \times (-1) = 2 \). Thus, \( \mathbf{Q} \) is antiparallel to \( \mathbf{P} \).
05

Summarize Results

From the calculations:1. Vectors \( \mathbf{P} \) and \( \mathbf{R} \) are perpendicular.2. Vectors \( \mathbf{Q} \) and \( \mathbf{R} \) are perpendicular.3. Vectors \( \mathbf{Q} \) and \( \mathbf{P} \) are antiparallel.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Perpendicular Vectors
In vector mathematics, two vectors are said to be perpendicular when they intersect at a right angle, sharing no common direction. This unique perpendicular characteristic can be confirmed through the dot product of the vectors. The dot product, a fundamental vector operation, equals zero when the vectors are perpendicular.

For instance, given two vectors \( \mathbf{P} = 3 \hat{\mathbf{x}} + 2 \hat{\mathbf{y}} - \mathbf{z} \) and \( \mathbf{R} = \hat{\mathbf{x}} - 2 \hat{\mathbf{y}} - \mathbf{z} \), we calculate their dot product as follows: \( (3)(1) + (2)(-2) + (-1)(-1) = 3 - 4 + 1 = 0 \). Since the product equals zero, these vectors are perpendicular.
  • Perpendicular vectors produce a zero dot product.
  • They intersect at a right angle.
Parallel Vectors
Two vectors are described as parallel if they have the same or opposite direction. The relationship of parallelism can be identified if one vector is a scalar multiple of the other. In essence, vector \( \mathbf{A} \) is parallel to vector \( \mathbf{B} \) if \( \mathbf{A} = k \mathbf{B} \), where \( k \) is a scalar value that is positive for parallel vectors and negative for antiparallel vectors.

For example, consider vectors \( \mathbf{P} = 3 \hat{\mathbf{x}} + 2 \hat{\mathbf{y}} - \mathbf{z} \) and \( \mathbf{Q} = -6 \hat{\mathbf{x}} - 4 \hat{\mathbf{y}} + 2 \mathbf{z} \). Here, \( \mathbf{Q} \) is \(-2\mathbf{P} \) because each component of \( \mathbf{Q} \) is \(-2 \) times the corresponding component in \( \mathbf{P} \), meaning \( \mathbf{Q} \) is antiparallel to \( \mathbf{P} \).
  • Parallel vectors keep the same direction.
  • Antiparallel vectors have opposing directions.
Dot Product
The dot product is a scalar value that is pivotal in assessing the angular relationship between two vectors. For vectors \( \mathbf{A} = a_1 \hat{x} + a_2 \hat{y} + a_3 \hat{z} \) and \( \mathbf{B} = b_1 \hat{x} + b_2 \hat{y} + b_3 \hat{z} \), the dot product is calculated as \( a_1b_1 + a_2b_2 + a_3b_3 \). This mathematical operation provides insight into whether vectors are aligned or orthogonal.

If the dot product equals zero, the vectors are perpendicular. A positive value indicates the vectors are more parallel than not, while a negative value suggests they are more antiparallel. This measure becomes essential in solving various problems across physics, engineering, and mathematics.
  • The dot product is critical for finding perpendicular vectors.
  • Useful in evaluating vector alignment.
Scalar Multiplication
Scalar multiplication involves the multiplication of a vector by a scalar (a real number). This process either magnifies or shrinks the vector's magnitude without altering its direction, unless the scalar is negative, which reverses the direction.

Consider vector \( \mathbf{U} = a \hat{x} + b \hat{y} + c \hat{z} \). If we multiply it by a scalar \( k \), the resulting vector is \( k \mathbf{U} = ka \hat{x} + kb \hat{y} + kc \hat{z} \).
  • Positive scalars elongate while maintaining direction.
  • Negative scalars invert the direction.
Scalar multiplication plays a significant role when determining if vectors are parallel or antiparallel, helping us understand the broader relationship within vector spaces.

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Most popular questions from this chapter

A sphere of radius \(a\) is centered at a point \(\mathbf{r}_{1}\). (a) Write out the algebraic equation for the sphere. (b) Write out a vector equation for the sphere. ANS. $$ \begin{array}{l} \text { (a) }\left(x-x_{1}\right)^{2}+\left(y-y_{1}\right)^{2}+\left(z-z_{1}\right)^{2}=a^{2} \\\ \text { (b) } \mathbf{r}=\mathbf{r}_{1}+\mathbf{a} . \end{array} $$ (a takes on all directions but has a fixed magnitude \(a\).)

The calculation of the magnetic moment of a current loop leads to the line integral $$ \oint \mathbf{r} \times d \mathbf{r} $$ (a) Integrate around the perimeter of a current loop (in the \(x y\) -plane) and show that the scalar magnitude of this line integral is twice the area of the enclosed surface. (b) The perimeter of an ellipse is described by \(\mathbf{r}=\hat{\mathbf{x}} a \cos \theta+\hat{\mathbf{y}} b \sin \theta\). From part (a) show that the area of the ellipse is \(\pi a b\).

A vector equation can be reduced to the form \(\mathbf{A}=\mathbf{B}\). From this show that the one vector equation is equivalent to three scalar equations. Assuming the validity of Newton's second law \(\mathbf{F}=m \mathbf{a}\) as a vector equation, this means that \(a_{x}\) depends only on \(F_{x}\) and is independent of \(F_{y}\) and \(F_{z}\).

The vertices of parallelogram \(A B C D\) are \((1,0,0),(2,-1,0),(0,-1,1)\), and \((-1,0,1)\) in order. Calculate the vector areas of triangle \(A B D\) and of triangle \(B C D\). Are the two vector areas equal? $$ \text { ANS. } \operatorname{Area}_{A B D}=-\frac{1}{2}(\hat{\mathbf{x}}+\hat{\mathbf{y}}+2 \hat{\mathbf{z}}) \text { . } $$

For \(\mathbf{A}=\hat{\mathbf{x}} A_{x}(x, y, z)\) and \(B=\hat{x} B_{x}(x, y, z)\) evaluate each term in the vector identity $$\nabla(\mathbf{A} \cdot \mathbf{B})=(\mathbf{B} \cdot \nabla) \mathbf{A}+(\mathbf{A} \cdot \nabla) \mathbf{B}+\mathbf{B} \times(\boldsymbol{\nabla} \times \mathbf{A})+\mathbf{A} \times(\boldsymbol{\nabla} \times \mathbf{B})$$ and verify that the identity is satisfied.

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