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(a) Define a slip system. (b) Do all metals have the same slip system? Why or why not?

Short Answer

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Explain your answer. Answer: No, not all metals have the same slip system. The type and number of slip systems in a metal depend on its crystal structure and specific atomic arrangement. Different metals have different crystal structures, leading to variations in their atomic arrangements and lattice geometry. This results in different planes and directions with the highest atomic density and packing for various crystal structures. These differences in slip systems among various metals affect their mechanical behaviors under stress and their overall properties.

Step by step solution

01

Define a slip system

A slip system is a combination of a slip plane and a slip direction within that plane, which controls the crystallographic motion of atoms within a material, particularly metals, under stress. It is essential for understanding the plastic deformation and the mechanical properties of materials. In a slip system, the slip plane is the plane with the highest density of atoms, and the slip direction is the direction with the highest atomic packing.
02

Discuss whether all metals have the same slip system

No, not all metals have the same slip system. The type and number of slip systems in a metal depend on its crystal structure and its specific atomic arrangement.
03

Explain the reasons behind the differences in slip systems

Different metals have different crystal structures, which leads to variations in their atomic arrangements and lattice geometry. Consequently, the planes with the highest atomic density and the directions with the highest atomic packing will be different for various crystal structures. For example, FCC (face-centered cubic) metals, such as aluminum and copper, have {111} planes as their slip planes and <110> directions as their slip directions, while BCC (body-centered cubic) metals, such as iron and chromium, have {110} planes as their slip planes and <111> directions as their slip directions. The differences in slip systems among various metals affect their mechanical behaviors under stress and their overall properties.

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Most popular questions from this chapter

A cylindrical specimen of a hypothetical metal alloy is stressed in compression. If its original and final diameters are \(30.00\) and \(30.04 \mathrm{~mm}\), respectively, and its final length is \(105.20 \mathrm{~mm}\), compute its original length if the deformation is totally elastic. The elastic and shear moduli for this alloy are \(65.5\) and \(25.4\) GPa, respectively.

(a) What is the driving force for recrystallization? (b) What is the driving force for grain growth?

The lower yield point for an iron that has an († average grain diameter of \(1 \times 10^{-2} \mathrm{~mm}\) is 230 MPa (33,000 psi). At a grain diameter of \(6 \times 10^{-3}\) \(\mathrm{mm}\), the yield point increases to \(275 \mathrm{MPa}(40,000\) psi). At what grain diameter will the lower yield point be \(310 \mathrm{MPa}(45,000 \mathrm{psi}) ?\)

For a brass alloy, the stress at which plastic deformation begins is \(345 \mathrm{MPa}(50,000 \mathrm{psi})\), and the modulus of elasticity is \(103 \mathrm{GPa}\left(15.0 \times 10^{6} \mathrm{psi}\right)\) (a) What is the maximum load that can be applied to a specimen with a cross- sectional area of \(130 \mathrm{~mm}^{2}\left(0.2 \mathrm{in} .{ }^{2}\right)\) without plastic deformation? (b) If the original specimen length is \(76 \mathrm{~mm}(3.0\) in.), what is the maximum length to which it can] be stretched without causing plastic deformation?

(a) Compare planar densities (Section \(3.11\) and Problem 3.60) for the \((100),(110)\), and (111) planes for FCC. (b) Compare planar densities (Problem 3.61) for the (100), (110), and (111) planes for BCC.

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