Chapter 8: Problem 36
Cite three metallurgical/processing techniques that are employed to enhance the creep resistance of metal alloys.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 8: Problem 36
Cite three metallurgical/processing techniques that are employed to enhance the creep resistance of metal alloys.
All the tools & learning materials you need for study success - in one app.
Get started for free
A large plate is fabricated from a steel alloy that has a plane strain fracture toughness of \(55 \mathrm{MPa} \sqrt{\mathrm{m}}(50 \mathrm{ksi} \sqrt{\mathrm{in} .})\). If, during service use, the plate is exposed to a tensile stress of \(200 \mathrm{MPa}(29,000 \mathrm{psi})\), determine the minimum length of a surface crack that will lead to fracture. Assume a value of \(1.0\) for \(Y\).
Suppose that a wing component on an aircraft is fabricated from an aluminum alloy that has a plane strain fracture toughness of \(40 \mathrm{MPa} \sqrt{\mathrm{m}}(36.4 \mathrm{ksi} \sqrt{\mathrm{in}}\).). It has been determined that fracture results at a stress of 365 MPa (53,000 psi) when the maximum internal crack length is \(2.5 \mathrm{~mm}(0.10 \mathrm{in} .)\). For this same component and alloy, compute the stress level at which fracture will occur for a critical internal crack length of \(4.0 \mathrm{~mm}(0.16 \mathrm{in}\).).
Briefly explain the difference between fatigue striations and beachmarks in terms of both (a) size and (b) origin.
A structural component in the form of a wide plate is to be fabricated from a steel alloy that has a plane strain fracture toughness of \(77.0 \mathrm{MPa} \sqrt{\mathrm{m}}\left(70.1 \mathrm{ksi} \sqrt{\mathrm{in}}_{\alpha}\right)\) and a yield strength of \(1400 \mathrm{MPa}(205,000 \mathrm{psi})\). The flaw size resolution limit of the flaw detection apparatus is \(4.0 \mathrm{~mm}\) (0.16 in.). If the design stress is one-half of the yield strength and the value of \(Y\) is \(1.0\), determine whether a critical flaw for this plate is subject to detection.
An aircraft component is fabricated from an aluminum alloy that has a plane strain fracture toughness of \(35 \mathrm{MPa} \sqrt{\mathrm{m}}(31.9 \mathrm{ksi} \sqrt{\text { in. }})\). It has been determined that fracture results at a stress of \(250 \mathrm{MPa}\) (36,250 psi) when the maximum (or critical) internal crack length is \(2.0 \mathrm{~mm}\) (0.08 in.). For this same component and alloy, will fracture occur at a stress level of \(325 \mathrm{MPa}\) (47,125 psi) when the maximum internal crack length is \(1.0 \mathrm{~mm}(0.04\) in.)? Why or why not?
What do you think about this solution?
We value your feedback to improve our textbook solutions.