/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 Calculate the force of attractio... [FREE SOLUTION] | 91影视

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Calculate the force of attraction between a \(\mathrm{K}^{+}\) and an \(\mathrm{O}^{2-}\) ion whose centers are separated by a distance of \(1.5 \mathrm{~nm}\).

Short Answer

Expert verified
Answer: The force of attraction between the K鈦 and O虏鈦 ion is approximately 28.76 x 10鈦宦孤 N.

Step by step solution

01

Identify charges of ions

The given ions are potassium ion (K鈦) and oxygen ion (O虏鈦). Potassium ion has a +1 positive charge, and oxygen ion has a -2 negative charge. Let's denote the charges as \(Q_1\) and \(Q_2\). Therefore, \(Q_1 = +1e\) and \(Q_2=-2e\), where \(e\) is the elementary charge (\(1.6 \times 10^{-19} \mathrm{C}\)).
02

Convert distance to meters

The given distance between ions is \(1.5 \mathrm{~nm}\). To use this value in Coulomb's law, we need to convert it to meters. We know that \(1\ \mathrm{nm} = 10^{-9}\mathrm{~m}\). So, the distance in meters is \(1.5 \times 10^{-9} \mathrm{~m}\).
03

Calculate force using Coulomb's law

According to Coulomb's law, the electrostatic force F between two charged particles is given by: \(F=\mathrm{k} \frac{\left|Q_1\right|\left|Q_2\right|}{r^2}\) Where \(F\) is the force of attraction, k is the electrostatic constant (\(k=8.99\times 10^9 \frac{N m^2}{C^2}\)), \(\left|Q_1\right|\) and \(\left|Q_2\right|\) are the magnitudes of the charges of the ions, \(r\) is the distance between the ions. Now, we can plug in the values and calculate the force : \(F = (8.99 \times 10^{9}\ \frac{N m^2}{C^2})\frac{(1 \times 1.6 \times 10^{-19}\ \mathrm{C})(2 \times 1.6 \times 10^{-19}\ \mathrm{C})}{(1.5\times 10^{-9}\ \mathrm{m})^2}\)
04

Solve for Force

Calculate the force by simplifying the above expression: \(F\approx (8.99 \times 10^{9}\ \frac{N m^2}{C^2})(3.2 \times 10^{-38}\ \mathrm{C^2})(2.25 \times 10^{-18}\ \mathrm{m^{-2}})\) \(F\approx (8.99 \times 10^{9})(3.2 \times 10^{-20})\) \(F\approx 28.76 \times 10^{-11}\ \mathrm{N}\) So, the force of attraction between the \(\mathrm{K}^{+}\) and an \(\mathrm{O}^{2-}\) ion is approximately \(28.76 \times 10^{-11} \mathrm{N}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electrostatic Force
Understanding the electrostatic force is essential when studying electrically charged particles such as ions. In the context of the textbook exercise, the electrostatic force refers to the invisible but measurable attraction or repulsion between two charged particles. This force is governed by Coulomb's law, which states that the magnitude of the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between the charges.

For those who might be encountering this concept for the first time, think of it like the force that holds two magnets together; only in this case, it's the charge, not magnetism, at play. The exercise demonstrates how two ions with opposing charges, specifically a potassium ion (K鈦) with a +1 charge and an oxygen ion (O虏鈦) with a -2 charge, are attracted to each other. This force can be measured, as seen in the solution where the actual numerical value of the force is calculated using the provided charges and distance in Coulomb's law formula.

In real-world contexts, this electrostatic force is fundamental in areas such as chemistry where it helps explain the interactions and bonds between atoms and molecules, enabling the formation of compounds like table salt or water.
Ionic Charge
Ionic charge plays a pivotal role in the textbook exercise, and it represents the electrical charge present on an ion which is an atom or molecule that has lost or gained one or more electrons. These ions are characterized as cations (positive charge) or anions (negative charge), depending on whether they have given up or taken on electrons. In our exercise, a potassium ion is a cation with a +1 charge, and an oxygen ion is an anion with a -2 charge.

It's like a name tag that tells other particles how to interact with the ion鈥攃harges with the same sign repel each other, and charges with different signs attract. The charges of the ions are used within Coulomb's law to determine the magnitude of the electrostatic force between them. Understanding the concept of ionic charge is crucial not only in physics but also in chemistry since it underlines the reason why certain elements combine to form ionic compounds. These charges, quantified by the fundamental unit of electric charge 'e' (the charge of a single proton), are used to compute interactions on the atomic scale.
Nanometers to Meters Conversion
Converting nanometers to meters is an essential step in the calculation of the electrostatic force between ions. The term 'nanometer' (nm) is a unit of length in the metric system, equal to one billionth of a meter, which is represented by the prefix 'nano' meaning 10鈦烩伖. In the provided example, the distance between the K鈦 and O虏鈦 ion centers is 1.5 nm, which we convert to meters because the SI unit for distance in the Coulomb's law equation is meters (m).

To convert from nanometers to meters, the value in nanometers is multiplied by 10鈦烩伖. Therefore, 1.5 nm becomes 1.5 x 10鈦烩伖 m. This conversion is pivotal for accurately using Coulomb's law since any discrepancies in the unit of distance can drastically change the calculated force. A handy trick for these conversions is to think of a nanometer as a really tiny distance, difficult to observe with the naked eye, often used to measure wavelengths of light or the size of molecules and atomic structures.

Key Conversion:

  • 1 nm = 10鈦烩伖 m
Always remember to perform this conversion when dealing with microscopic distances to seamlessly bridge the gap between the scales of the atomic world and the larger world we measure in meters.

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Most popular questions from this chapter

6 Allowed values for the quantum numbers of electrons are as follows: $$ \begin{aligned} n &=1,2,3, \ldots \\ l &=0,1,2,3, \ldots, n-1 \\ m_{l} &=0, \pm 1, \pm 2, \pm 3, \ldots, \pm l \\ m_{s} &=\pm \frac{1}{2} \end{aligned} $$ The relationships between \(n\) and the shell designations are noted in Table 2.1. Relative to the subshells, \(l=0\) corresponds to an \(s\) subshell \(l=1\) corresponds to a \(p\) subshell \(l=2\) corresponds to a \(d\) subshell \(l=3\) corresponds to an \(f\) subshell For the \(K\) shell, the four quantum numbers for each of the two electrons in the \(1 s\) state, in the order of \(n l m_{i} m_{s}\), are \(100 \frac{1}{2}\) and \(100\left(-\frac{1}{2}\right)\) Write the four quantum numbers for all of the electrons in the \(L\) and \(M\) shells, and note which correspond to the \(s, p\), and \(d\) subshells.

Cite the difference between atomic mass and atomic weight.

Without consulting Figure 2.6 or Table \(2.2,\) determine whether each of the electron configurations given below is an inert gas, a halogen, an alkali metal, an alkaline earth metal, or a transition metal. Justify your choices. (a) \(1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{5}\) (b) \(1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{7} 4 s^{2}\) (c) \(1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{10} 4 s^{2} 4 p^{6}\) (d) \(1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{1}\) (e) $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{10} 4 s^{2} 4 p^{6} 4 d^{5} 5 s^{2}$ (f) \(1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2}\)

(a) What electron subshell is being filled for the rare earth series of elements on the periodic table? (b) What electron subshell is being filled for the actinide series?

Explain why hydrogen fluoride (HF) has a higher boiling temperature than hydrogen chloride (HCl) \(\left(19.4^{\circ} \mathrm{C}\right.\) vs. \(\left.-85^{\circ} \mathrm{C}\right)\), even though HF has a lower molecular weight.

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