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At temperatures between \(775^{\circ} \mathrm{C}(1048 \mathrm{~K})\) and \(1100^{\circ} \mathrm{C}(1373 \mathrm{~K})\), the activation energy and preexponential for the diffusion coefficient of \(\mathrm{Fe}^{2+}\) in \(\mathrm{FeO}\) are \(102,000 \mathrm{~J} / \mathrm{mol}\) and \(7.3 \times 10^{-8} \mathrm{~m}^{2} / \mathrm{s}\), respectively. Compute the mobility for an \(\mathrm{Fe}^{2+}\) ion at \(1000^{\circ} \mathrm{C}(1273 \mathrm{~K})\).

Short Answer

Expert verified
Answer: The mobility of the Fe虏鈦 ion at 1000掳C (1273 K) is approximately 2.16 脳 10鈦烩伕 m虏/(V路s).

Step by step solution

01

Write down the Arrhenius equation

The Arrhenius equation is given as: $$D = D_0 \cdot e^{\frac{-E_a}{RT}}$$ Where: - \(D\) is the diffusion coefficient - \(D_0\) is the pre-exponential for the diffusion coefficient - \(E_a\) is the activation energy - \(R\) is the gas constant \((8.314 \mathrm{~J} / \mathrm{mol} \cdot \mathrm{K})\) - \(T\) is the temperature in Kelvin
02

Plug in the given values into the Arrhenius equation

Now, we can plug in the values given in the exercise: \(D_0 = 7.3 \times 10^{-8} \mathrm{~m}^{2} / \mathrm{s}\) \(E_a = 102,000 \mathrm{~J} / \mathrm{mol}\) \(T = 1273 \mathrm{~K}\) Plug these values into the Arrhenius equation: $$D = (7.3 \times 10^{-8}) \cdot e^{\frac{-102,000}{(8.314 \cdot 1273)}}$$
03

Calculate the diffusion coefficient

Now, simplify and find the value of the diffusion coefficient: $$D \approx 4.29 \times 10^{-11} \mathrm{~m}^{2} / \mathrm{s}$$
04

Calculate the mobility of the \(\mathrm{Fe}^{2+}\) ion

The mobility (\(\mu\)) of an ion can be calculated using the formula: $$\mu = \frac{qD}{RT}$$ Where: - \(\mu\) is the mobility of ion \(\mathrm{Fe}^{2+}\) - \(q\) is the charge of the ion in Coulombs, which is \(2 \times 1.6 \times 10^{-19} \mathrm{~C}\) for \(\mathrm{Fe}^{2+}\) ion - \(D\) is the diffusion coefficient (\((4.29 \times 10^{-11} \mathrm{~m}^{2} / \mathrm{s})\)) - \(R\) is the gas constant \((8.314 \mathrm{~J} / \mathrm{mol} \cdot \mathrm{K})\) - \(T\) is the temperature in Kelvin (1273) Plug the values into the formula: $$\mu = \frac{(2 \times 1.6 \times 10^{-19})(4.29 \times 10^{-11})}{(8.314 \cdot 1273)}$$
05

Find the mobility of the \(\mathrm{Fe}^{2+}\) ion

Simplify and find the value of the mobility: $$\mu \approx 2.16 \times 10^{-8} \mathrm{~m}^{2} / (\mathrm{V} \cdot \mathrm{s})$$ Thus, the mobility of the \(\mathrm{Fe}^{2+}\) ion at \(1000^{\circ} \mathrm{C}(1273 \mathrm{~K})\) is approximately \(2.16 \times 10^{-8} \mathrm{~m}^{2} / (\mathrm{V} \cdot \mathrm{s})\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Arrhenius Equation
The Arrhenius equation is fundamental for understanding how temperature influences reaction rates, including diffusion processes. It's expressed as \[D = D_0 \cdot e^{\frac{-E_a}{RT}}\] where
  • \(D\) is the diffusion coefficient,
  • \(D_0\) is the pre-exponential factor indicating the frequency and orientation of molecular collisions,
  • \(E_a\) represents the activation energy required to initiate the diffusion,
  • \(R\) is the ideal gas constant, and
  • \(T\) is the absolute temperature in Kelvin.

The exponent \( -E_a/(RT) \) illustrates the exponential decrease in diffusion rate with the increase of activation energy or the decrease of temperature, showing how crucial these variables are in the diffusion process. By plugging in the relevant values, students can calculate the diffusion coefficient at any given temperature, providing insights into the mobility of particles under thermal influence.
Activation Energy
Activation energy (\(E_a\)) is the required energy barrier that reactants must overcome to transform into products. In the context of diffusion, it's the minimum energy needed for particles to move from one location to another. This concept is central because it determines how easily particles can migrate through materials, like \(Fe^{2+}\) ions in \(FeO\).

The higher the activation energy, the lower the diffusion coefficient at a given temperature, as described by the Arrhenius equation. Knowing the activation energy, which in the case of \(Fe^{2+}\) ions is 102,000 J/mol, allows us to predict how temperature changes will affect their diffusion. The activation energy is a constant for a given material and is significant in estimating reaction rates and understanding the characteristics of a material's structure at an atomic level.
Ion Mobility
Ion mobility (\(\mu\)) refers to the movement of an ion under the influence of an electric field, which is directly related to the diffusion coefficient (\(D\)) through the equation \[\mu = \frac{qD}{RT}\] where
  • \(\mu\) is the mobility,
  • \(q\) is the ion charge,
  • \(D\) is the diffusion coefficient,
  • \(R\) is the gas constant, and
  • \(T\) is the temperature in Kelvin.

Ion mobility is a measure of how fast an ion can travel in a certain medium when an electric field is applied. The mobility of ions, such as \(Fe^{2+}\) at 1273 K, tells us how efficient the ions are at conducting current in that material. Higher mobility indicates faster ion movement, which is critical for applications in battery technology and semiconductor devices. The derived mobility, in this case, demonstrates the feasibility of using \(FeO\) in different electrochemical processes.

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Most popular questions from this chapter

(a) Calculate the drift velocity of electrons in germanium at room temperature and when the magnitude of the electric field is \(1000 \mathrm{~V} / \mathrm{m}\). (b) Under these circumstances, how long does it take an electron to traverse a \(25-\mathrm{mm}\) (1-in.) length of crystal?

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