Chapter 10: Problem 31
Cite two reasons why martensite is so hard and brittle.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 10: Problem 31
Cite two reasons why martensite is so hard and brittle.
All the tools & learning materials you need for study success - in one app.
Get started for free
For a eutectoid steel, describe isothermal heat treatments that would be required to yield specimens having the following Rockwell hardnesses: (a) \(93 \mathrm{HRB}\) (b) \(40 \mathrm{HRC}\) (c) \(27 \mathrm{HRC}\)
(a) From the curves shown in Figure \(10.11\) and using Equation 10.18, determine the rate of recrystallization for pure copper at the several temperatures. (b) Make a plot of \(\ln (\) rate) versus the reciprocal of temperature (in \(\mathrm{K}^{-1}\) ), and determine the activation energy for this recrystallization process. (See Section 5.5.) (c) By extrapolation, estimate the length of time required for \(50 \%\) recrystallization at room temperature, \(20^{\circ} \mathrm{C}(293 \mathrm{~K})\).
(a) Briefly describe the phenomena of superheating and supercooling. (b) Why do these phenomena occur?
Briefly describe the simplest heat treatment procedure that would be used in converting a \(0.76 \mathrm{wt} \% \mathrm{C}\) steel from one microstructure to the other, as follows: (a) Spheroidite to tempered martensite (b) Tempered martensite to pearlite (c) Bainite to martensite (d) Martensite to pearlite (e) Pearlite to tempered martensite (f) Tempered martensite to pearlite (g) Bainite to tempered martensite (h) Tempered martensite to spheroidite
Name the microstructural products of eutectoid iron-carbon alloy \((0.76 \mathrm{wt} \% \mathrm{C})\) specimens that are first completely transformed to austenite, then cooled to room temperature at the following rates: (a) \(200^{\circ} \mathrm{C} / \mathrm{s}\), (b) \(100^{\circ} \mathrm{C} / \mathrm{s}\), and (c) \(20^{\circ} \mathrm{C} / \mathrm{s}\).
What do you think about this solution?
We value your feedback to improve our textbook solutions.