/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 1 Name the two stages involved in ... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 10: Problem 1

Name the two stages involved in the formation of particles of a new phase. Briefly describe each.

Short Answer

Expert verified
Answer: The two stages involved in the formation of particles of a new phase are nucleation and growth. Nucleation is the initial clustering of molecules or atoms to create a stable nucleus, while growth involves additional molecules or atoms attaching to the nucleus, creating larger particles of the new phase.

Step by step solution

01

Stage 1: Nucleation

Nucleation is the first stage in the formation of particles of a new phase. At this stage, a small part of the new phase (called a nucleus) starts to form amidst the existing phase, usually under specific conditions such as changes in temperature, pressure, or composition. It involves the initial clustering of molecules or atoms, overcoming an energy barrier to create a stable nucleus. This process can be homogeneous, meaning it occurs uniformly throughout the system, or heterogeneous, meaning it occurs at specific sites such as on surface imperfections or inclusions.
02

Stage 2: Growth

Growth is the second stage in the formation of particles of a new phase. Once the nucleus is stable, additional molecules or atoms begin to attach to the nucleus and create larger particles of the new phase. This process occurs by means of diffusion, where atoms or molecules in the existing phase move towards the nucleus of the new phase and deposit onto it. The growth stage consists of the development and expansion of these nuclei until they eventually form the new phase, which can lead to phase separation or transformations in the system.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Name the microstructural products of 4340 alloy steel specimens that are first completely transformed to austenite, then cooled to room temperature at the following rates: (a) \(10^{\circ} \mathrm{C} / \mathrm{s}\) (b) \(1^{\circ} \mathrm{C} / \mathrm{s}\) (c) \(0.1^{\circ} \mathrm{C} / \mathrm{s}\) (d) \(0.01^{\circ} \mathrm{C} / \mathrm{s}\)

On the basis of diffusion considerations, explain why fine pearlite forms for the moderate cooling of austenite through the eutectoid temperature, whereas coarse pearlite is the product for relatively slow cooling rates.

In terms of heat treatment and the development of microstructure, what are two major limitations of the iron-iron carbide phase diagram?

Briefly explain why the hardness of tempered martensite diminishes with tempering time (at constant temperature) and with increasing temperature (at constant tempering time).

Compute the rate of some reaction that obeys Avrami kinetics, assuming that the constants \(n\) and \(k\) have values of \(3.0\) and \(7 \times 10^{-3}\), respectively, for time expressed in seconds.
See all solutions

Recommended explanations on Physics Textbooks

Particle Model of Matter

Read Explanation

Fluids

Read Explanation

Force

Read Explanation

Electric Charge Field and Potential

Read Explanation

Dynamics

Read Explanation

Scientific Method Physics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.