Chapter 3: Problem 1
What is the difference between atomic structure and crystal structure?
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These are the key concepts you need to understand to accurately answer the question.
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Chapter 3: Problem 1
What is the difference between atomic structure and crystal structure?
These are the key concepts you need to understand to accurately answer the question.
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(a) Derive the planar density expression for the HCP (0001) plane in terms of the atomic radius \(R.\) (b) Compute the planar density value for this same plane for titanium.
Using the Molecule Definition Utility found in both "Metallic Crystal Structures and Crystallography" and "Ceramic Crystal Structures" modules of \(V M S E,\) located on the book's web site [www.wiley.com/college/callister (Student Companion Site)], generate (and print out) a three-dimensional unit cell for \(\beta\) tin given the following: (1) the unit cell is tetragonal with \(a=0.583 \mathrm{nm}\) and \(c=0.318\) \(\mathrm{nm},\) and (2) \(\mathrm{Sn}\) atoms are located at the following point coordinates: $$\begin{array}{ll} 000 & 011 \\ 100 & \frac{1}{2} 0 \frac{3}{4} \\ 110 & \frac{1}{2} 1 \frac{3}{4} \\ 010 & 1 \frac{1}{2} \frac{1}{4} \\ 001 & 0 \frac{1}{2} \frac{1}{4} \\ 101 & \frac{1}{2} \frac{1}{2} \frac{1}{2} \\ 111 \end{array}$$
The metal niobium has a BCC crystal structure. If the angle of diffraction for the (211) set of planes occurs at \(75.99^{\circ}\) (first-order reflection) when monochromatic x-radiation having a wavelength of \(0.1659 \mathrm{nm}\) is used, compute (a) the interplanar spacing for this set of planes and (b) the atomic radius for the niobium atom.
Cobalt has an HCP crystal structure, an atomic radius of \(0.1253 \mathrm{nm},\) and a \(c / a\) ratio of 1.623 Compute the volume of the unit cell for Co.
Calculate the radius of a tantalum atom, given that Ta has a BCC crystal structure, a density of \(16.6 \mathrm{g} / \mathrm{cm}^{3},\) and an atomic weight of \(180.9 \mathrm{g} / \mathrm{mol}.\)
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