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What torque will increase angular velocity of a solid disc of mass \(16 \mathrm{~kg}\) and diameter \(1 \mathrm{~m}\) from zero to 120 rpm in \(8 \mathrm{~s}\) ? (a) \(\frac{\pi}{4} \mathrm{~N}-\mathrm{m}\) (b) \(\frac{\pi}{2} \mathrm{~N}-\mathrm{m}\) (c) \(\frac{\pi}{3} \mathrm{~N}-\mathrm{m}\) (d) \(\pi \mathrm{N}-\mathrm{m}\)

Short Answer

Expert verified
The torque needed is \( \pi \) Nm, which matches option (d).

Step by step solution

01

Convert Angular Velocity to Radians per Second

First, we need to convert the final angular velocity from revolutions per minute (rpm) to radians per second. Given, the final angular velocity \( \omega \) is 120 rpm.To convert from rpm to rad/s, use the formula:\[ \omega = 120 \times \frac{2\pi}{60} \]Calculating gives:\[ \omega = 4 \pi \text{ rad/s} \]
02

Find the Moment of Inertia

The formula for the moment of inertia \( I \) of a solid disc about its center is:\[ I = \frac{1}{2} m r^2 \]where \( m = 16 \text{ kg} \) is the mass and \( r = 0.5 \text{ m} \) (since the diameter \( d = 1 \text{ m} \)) is the radius. Substituting the known values gives:\[ I = \frac{1}{2} \times 16 \times (0.5)^2 = 2 \text{ kg m}^2 \]
03

Calculate Angular Acceleration

The angular acceleration \( \alpha \) can be calculated using the formula:\[ \alpha = \frac{\omega_f - \omega_i}{t} \]where \( \omega_f = 4 \pi \) rad/s, \( \omega_i = 0 \) rad/s (initial angular velocity), and \( t = 8 \) s (time).So:\[ \alpha = \frac{4\pi - 0}{8} = \frac{\pi}{2} \text{ rad/s}^2 \]
04

Calculate the Required Torque

Finally, use the relation between torque \( \tau \), moment of inertia \( I \), and angular acceleration \( \alpha \):\[ \tau = I \alpha \]Substitute \( I = 2 \) kg m\(^2\) and \( \alpha = \frac{\pi}{2} \) rad/s\(^2\):\[ \tau = 2 \times \frac{\pi}{2} = \pi \text{ Nm} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Velocity
Angular velocity refers to the rate at which an object rotates or spins around an axis. It's the rotational counterpart to linear velocity and is measured in radians per second (rad/s). In this exercise, the angular velocity of the solid disc changes from zero to 120 rpm.
To work with calculations involving angular velocity in physics, it's essential to convert rpm (revolutions per minute) into rad/s, since radians are the standard unit for angular measurements. Each revolution is equivalent to 2Ï€ radians. Therefore, the conversion from rpm to rad/s involves multiplying by \( \frac{2\pi}{60} \), because there are 60 seconds in a minute.
The formula used here is \( \omega = \text{rpm} \times \frac{2\pi}{60} \). By plugging in 120 rpm, we find \( \omega = 4 \pi \text{ rad/s} \). Understanding this conversion is crucial when dealing with problems involving rotational motion.
Moment of Inertia
The moment of inertia, often symbolized as \( I \), is a measure of an object's resistance to changes in its rotational motion. It is analogous to mass in linear motion.
For a solid disc, the formula to calculate moment of inertia about its center is \( I = \frac{1}{2} m r^2 \), where \( m \) is the mass and \( r \) is the radius of the disc. This formula shows that the moment of inertia depends both on the shape of the object and the distribution of mass relative to the axis of rotation.
In our exercise, using the mass \( m = 16 \text{ kg} \) and radius \( r = 0.5 \text{ m} \) (half of the diameter), the moment of inertia is calculated as \( I = \frac{1}{2} \times 16 \times (0.5)^2 = 2 \text{ kg m}^2 \). The understanding of how to compute the moment of inertia for different shapes is crucial when analyzing rotational dynamics.
Angular Acceleration
Angular acceleration, denoted as \( \alpha \), is the rate of change of angular velocity over time. It tells us how quickly an object is speeding up or slowing down its rotation. It's similar to linear acceleration but in the context of rotational motion.
The formula for angular acceleration is \( \alpha = \frac{\omega_f - \omega_i}{t} \), where \( \omega_f \) is the final angular velocity, \( \omega_i \) is the initial angular velocity, and \( t \) is the time taken. In this problem, the initial angular velocity \( \omega_i \) is 0 (since the disc starts from rest), and \( \omega_f = 4\pi \) rad/s.
With a given time \( t = 8 \text{ s} \), the angular acceleration turns out to be \( \alpha = \frac{4\pi - 0}{8} = \frac{\pi}{2} \text{ rad/s}^2 \). This concept is vital for understanding how forces affect rotational motion.
Solid Disc
A solid disc is a common geometric shape used in physics problems involving rotational motion. It is defined as a flat, circular object with uniform thickness and mass distribution.
In physics, especially when calculating dynamics of rotation, it's important to know how the mass is distributed because this affects the moment of inertia. For a solid disc rotating about an axis through its center and perpendicular to its plane, the standard moment of inertia is \( I = \frac{1}{2} m r^2 \).
This property is vital as it influences how the disc will react to applied forces in terms of starting or maintaining rotation. A solid disc's simple geometric shape helps in validating and applying basic formulas, making it a staple example in understanding the fundamentals of rotational dynamics.

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Most popular questions from this chapter

Three particles each of mass \(m\) gram, are situated at the vertices of an equilateral triangle \(A B C\) of side \(l \mathrm{~cm}\) (as shown in figure). The moment of inertia of the system about a line \(A X\) perpendicular to \(A B\) and in the plane of \(A B C\) in \(\mathrm{g}-\mathrm{cm}^{2}\) unit will be (a) \(\frac{3}{4} m l^{2}\) (b) \(2 \mathrm{ml}^{2}\) (c) \(\frac{5}{4} m l^{2}\) (d) \(\frac{3}{2} m l^{2}\)

Assertion Moment of inertia of circular ring about a given axis is more than moment of inertia of the cireular disc of same mass and same size, about the same axis. Reason The circular ring hollow so its moment of inertia is more than circular disc which is solid.

A particle performs uniform circular motion with an angular momentum \(L\), if the frequency of particles motion is doubled and its kinetic energy is halved, the angular momentum becomes (a) \(4 L\) (b) \(0.5 L\) [c) \(2 L\) (d) \(0.25 L\)

The angular velocity of minutes hand of a watch is (a) \(\frac{\pi}{30} \mathrm{rad} s^{-1}\) (b) \(\frac{\pi}{60} \mathrm{rad} \mathrm{s}^{-1}\) (c) \(\frac{\pi}{1800} \mathrm{rad} \mathrm{s}^{-1}\) (d) \(\frac{\pi}{3600} \mathrm{rad} \mathrm{s}^{-1}\)

Two wheels \(A\) and \(B\) are mounted on the same axle. Moment of inertia of \(A\) is \(6 \mathrm{kgm}^{2}\) and it is rotating at \(600 \mathrm{rpm}\) when \(B\) is at rest. What is moment of inertia of \(B\), if their combined speed is 400 rpm? (a) \(8 \mathrm{~kg} \mathrm{~m}^{2}\) (b) \(4 \mathrm{~kg} \mathrm{~m}^{2}\) (c) \(3 \mathrm{~kg} \mathrm{~m}^{2}\) (d) \(5 \mathrm{~kg} \mathrm{~m}^{2}\)

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