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In a one dimensional collision between two identical partieles \(A\) and \(B\), where \(B\) is stationary and \(A\) has momentum \(p\) before impact. During impact \(B\) gives an impulse \(J\) to \(A\). Then coefficient of restitution between the two is (a) \(\frac{2 J}{p}-1\) (b) \(\frac{2 J}{p}+1\) (c) \(\frac{J}{p}+1\) (d) \(\frac{J}{p}-1\)

Short Answer

Expert verified
The coefficient of restitution is \(\frac{2 J}{p} - 1\), so the correct answer is (a).

Step by step solution

01

Understand the Problem

We need to determine the coefficient of restitution for a one-dimensional collision where particle A has an initial momentum \(p\) and particle B is stationary. Particle B gives an impulse \(J\) to particle A during the collision.
02

Define Coefficient of Restitution

The coefficient of restitution \(e\) is defined as the ratio of the relative speed of separation to the relative speed of approach. For a system with initial and final velocities, \(e = \frac{v_{B,f} - v_{A,f}}{v_{A,i} - v_{B,i}}\). Since \(B\) is stationary initially, \(v_{B,i} = 0\). Thus, \(e = \frac{v_{B,f} - v_{A,f}}{v_{A,i}}\).
03

Analyze Initial Conditions

Initially, particle A has momentum \(p\) and moves with velocity \(v_{A,i} = \frac{p}{m}\), where \(m\) is the mass of the particles. Particle B is at rest, so \(v_{B,i} = 0\).
04

Apply Impulse-Momentum Theorem

The impulse received by A, \(J = m(v_{A,f} - v_{A,i})\). Since B imparts this impulse, it moves with the velocity \(v_{B,f} = \frac{J}{m}\) after the collision.
05

Use Momentum Conservation

The total momentum before collision \(p_A = m \times v_{A,i}\) and after collision \(m \times v_{A,f} + m \times v_{B,f} = p\). Use these to express \(v_{A,f}\) and \(v_{B,f}\) in terms of \(p\) and \(J\).
06

Calculate Coefficient of Restitution

Use the expression derived earlier: \(e = \frac{v_{B,f} - v_{A,f}}{v_{A,i}}\). Substitute \(v_{B,f} = \frac{J}{m}\) and \(v_{A,i} = \frac{p}{m}\), then solve for \(e\) in terms of \(J\) and \(p\). After calculation, \(e = \frac{2J}{p} - 1\).
07

Identify the Correct Option

From the choices provided, compare with your calculation result. The correct option matches choice (a) \(\frac{2 J}{p} - 1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

one-dimensional collision
In physics, a one-dimensional collision refers to an event where two objects collide along a single straight line. For such a collision, focusing on what changes and what remains constant can simplify the problem. In the scenario provided, particle A moves towards a stationary particle B in a straight path. When A collides with B, their interaction is restricted to this one-dimensional trajectory.
Understanding one-dimensional collisions involves observing parameters such as velocity, mass, and momentum of the objects involved. Here, particle A enters the collision with an initial momentum calculated using mass and velocity, expressed as \( p = m \times v \).
One-dimensional collisions can be elastic or inelastic. The degree to which kinetic energy is conserved or transferred defines this category. Applying basic concepts such as the conservation of momentum and analyzing forces acting during the collision guides us to solutions that fit real-world observations of such one-dimensional collisions.
impulse-momentum theorem
The impulse-momentum theorem is a fundamental concept in physics that links the impulse applied to an object with the change in its momentum. According to this theorem, the impulse imparted to an object is equal to the change in its momentum. Mathematically, it is expressed as \( J = \Delta p \), where \( J \) is the impulse, and \( \Delta p \) is the change in momentum.
This theorem is especially useful in collision problems, as seen with particles A and B. During their one-dimensional collision, particle B gives an impulse \( J \) to A, which significantly changes A's momentum. If A's initial momentum is \( p \) and its final momentum is less than \( p \), the impulse will directly account for this change.
  • Impulse is described as the force applied over the time period of the collision.
  • Momentum change helps in determining velocities post-collision.
By applying this theorem, we can connect the observable force effects during the collision to the system's intrinsic properties, allowing for calculations of quantities like the coefficient of restitution.
momentum conservation
Momentum conservation is a core principle in mechanics, stating that the total momentum of a closed system remains constant if no external forces act on it. In the context of our one-dimensional collision, total system momentum (both particles A and B) before and after the collision is conserved.
Before the collision, only particle A has momentum, and it is quantified as \( p = m \times v_{A,i} \). After the collision, both particles share this momentum, with individual contributions of \( v_{A,f} \) and \( v_{B,f} \).
  • Total momentum before: \( p = m \times v_{A,i} \)
  • Total momentum after: \( m \times v_{A,f} + m \times v_{B,f} = p \)
This conservation allows the calculation of particle velocities post-impact through known initial conditions.
In solving the presented problem, applying momentum conservation enables us to express post-collision velocities \( v_{A,f} \) and \( v_{B,f} \) in terms of given impulse \( J \) and initial momentum \( p \). Thus, it not only verifies the system's interactions but also directly aids in computing the coefficient of restitution.

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