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Which of the following is not a perfectly inelastic collision? (a) Striking of two glass ball (b) A bullet striking a bag of sand (c) An electron captured by a proton (d) A man jumping onto a moving car

Short Answer

Expert verified
Option (d) is not a perfectly inelastic collision.

Step by step solution

01

Understanding Perfectly Inelastic Collisions

A perfectly inelastic collision occurs when two objects collide and move together as a single body after the collision. This means that both objects reach the same final velocity, and maximum kinetic energy is lost while conserving momentum.
02

Analyze Option (a)

In the case of two glass balls colliding, the collision can lead to the two objects sticking together and moving as one, which describes a perfectly inelastic collision.
03

Analyze Option (b)

When a bullet strikes a bag of sand and embeds itself inside, they move together as a single entity. This represents a perfectly inelastic collision.
04

Analyze Option (c)

An electron being captured by a proton results in the formation of a hydrogen atom. The two particles stick together, which fits the definition of a perfectly inelastic collision.
05

Analyze Option (d)

A man jumping onto a moving car involves the two moving together but is complicated by external forces such as friction and air resistance, making it less straightforward to be perfectly inelastic. This situation doesn't typically define a classic perfectly inelastic collision.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Momentum Conservation
In the world of physics, momentum conservation is a fundamental principle, especially when discussing collision events. During a collision, momentum–a quantity defined as the product of an object's mass and its velocity–is always conserved. This means that the total momentum before the collision will equal the total momentum after the collision, regardless of the type of collision.

This principle is especially crucial when analyzing perfectly inelastic collisions. In such events, two objects collide and stick together, forming a single body post-collision. The conservation of momentum allows us to calculate the final velocity of the combined mass after the collision. For instance, if a bullet strikes a stationary bag of sand, the bullet and the sand will have a combined velocity due to the conservation of momentum.

When we're solving physics problems, you often start with the equation:\[m_1v_1 + m_2v_2 = (m_1 + m_2) v_f\] where:
  • \(m_1\) and \(m_2\) are the masses of the two colliding objects
  • \(v_1\) and \(v_2\) are their initial velocities
  • \(v_f\) is the final common velocity
This formula is an illustration of the momentum conservation principle and essential in understanding how objects behave after perfectly inelastic collisions.
Kinetic Energy
Another important concept to understand in collisions, particularly perfectly inelastic ones, is kinetic energy. In physics, kinetic energy is the energy an object possesses due to its motion. During a perfectly inelastic collision, not all kinetic energy is conserved.

Instead, the energy is transformed into other forms, such as heat, sound, or deformation of the objects involved. The loss of kinetic energy is one of the defining features of perfectly inelastic collisions, since the objects merge, losing relative motion.

The formula for kinetic energy is given by:\[KE = \frac{1}{2} mv^2\] This means if two objects collide and join, their combined kinetic energy post-collision will be less than the sum of their individual kinetic energies pre-collision. Although kinetic energy is not conserved, determining the energy transformation provides insight into the nature and aftermath of the collision, such as why a bullet ceases its travel after embedding in a sandbag, yet heat is generated.

It's critical to recognize this dissipation of kinetic energy when analyzing inelastic collisions, as it differentiates them starkly from elastic collisions, where kinetic energy is conserved.
Collision Types
Collisions are categorized into different types, primarily elastic, inelastic, and perfectly inelastic collisions. Understanding these types is crucial in determining what happens during an impact, such as determining whether kinetic energy is conserved.

1. **Elastic Collisions**: These are situations where both momentum and kinetic energy are conserved. After such collisions, objects rebound off each other, without any loss of overall kinetic energy. These are idealized scenarios often used in theoretical physics.

2. **Inelastic Collisions**: During these events, momentum is conserved, but kinetic energy is not. The objects may bounce off with different energies compared to what they started with. However, they don't stick together as with perfectly inelastic collisions.

3. **Perfectly Inelastic Collisions**: Here, you see the objects moving together as a single entity post-impact. Though momentum is maintained, maximum kinetic energy is lost, as seen with a bullet lodging into a sandbag. Often these are the most impactful or tangible interactions, as the merged motion signifies a complete loss of internal kinetic motion among the objects.

Knowing these types helps to analyze real-world problems effectively. Determining which type of collision has occurred can influence our understanding of the aftermath, such as when judging if objects will stay together or separate after impact.

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Most popular questions from this chapter

Two identical blocks \(A\) and \(B\), each of mass \(m\) resting on smooth floor are connected by a light spring of natural length \(L\) and spring constant \(k\) with the spring at its natural length. A third identical block \(C\) (mass \(m\) ) moving with a speed \(v\) along the line joining \(A\) and \(B\) collides with \(A\). The maximum compression in the spring is (a) \(v \sqrt{\frac{m}{2 k}}\) (b) \(m \sqrt{\frac{v}{2 k}}\) (c) \(\sqrt{\frac{m v}{K}}\) (d) \(\frac{m v}{2 k}\)

A bomb is kept stationary at a point. It suddenly explodes into two fragments of masses \(1 \mathrm{~g}\) and \(3 \mathrm{~g}\). The total kinetic energy of the fragments is \(6.4 \times 10^{4} \mathrm{~J}\). What is the kinetie energy of the smaller fragment? (a) \(2.5 \times 10^{4} \mathrm{~J}\) (b) \(3.5 \times 10^{4} \mathrm{~J}\) (c) \(\left.4.8 \times 10^{4}\right]\) (d) \(\left.5.2 \times 10^{4}\right]\)

A body in equilibrium may not have (a) momentum (b) velacity (c) acceleration (d) kinetic energy

Two blocks of masses \(m_{1}\) and \(m_{2}\) are connected by a massless spring and placed at smooth surface. The spring initially stretched and released. Then (a) the momentum of each particle remains constant separately (b) the magnitude of momentum of both bodies are same to each other (c) the mechanical enetgy of system remains constant (d) both (b) and \((c)\) are correct

A body of mass \(3 \mathrm{~kg}\) is moving with a velocity of \(4 \mathrm{~ms}^{-1}\) towards right, collides head on with a body of mass \(4 \mathrm{~kg}\) moving in opposite direction with a velocity of \(3 \mathrm{~ms}^{-1}\). After collision the two bodies stick together and move with a common velocity, which is (a) zero (b) \(12 \mathrm{~ms}^{-1}\) toward left (c) \(12 \mathrm{~ms}^{-1}\) towards right (d) \(\frac{12}{7} \mathrm{~ms}^{-1}\) towards left

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