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A loaded spring gun of mass \(M\) fires a shot of mass \(m\) with a velocity \(v\) at an angle of elevation \(\theta\). The gun was initially at rest on a horizontal frictionless surface. After firing, the centre of mass of gun-shot system (a) moves with a velocity \(\frac{m v}{M}\) (b) moves with a velocity \(\frac{\pi n}{M \cos \theta}\) in the horizontal direction (c) remains at rest (d) moves with velocity \(\frac{(M-m) v}{(M+m)}\) in the horizontal direction

Short Answer

Expert verified
(c) remains at rest.

Step by step solution

01

Understand the System

The given exercise involves a spring gun system where a gun of mass \(M\) fires a shot of mass \(m\). The system is initially at rest on a frictionless surface. When the gun fires the shot, motion will be analyzed using conservation of linear momentum, since there is no external horizontal force acting on the system.
02

Apply Conservation of Momentum

The principle of conservation of linear momentum states that the total momentum of an isolated system remains constant if no external forces are applied. Initially, the system is at rest, so the total initial momentum is zero. After firing, the momentum of the shot \((m\cdot v \cos \theta)\) and the momentum of the gun \((M\cdot V)\) must be equal and opposite: \[m \cdot v \cos \theta = M \cdot V\] Solving for \(V\): \[V = \frac{m \cdot v \cos \theta}{M}\] This velocity \(V\) is the velocity of the gun in the opposite direction of the bullet's horizontal component.
03

Analyze the Center of Mass Motion

The center of mass of the system can be described by the formula: \[v_{\text{cm}} = \frac{M \cdot V + m \cdot v}{M+m}\] However, since the total momentum was initially zero and remains zero (isolated system), the velocity of the center of mass remains zero. Thus: \[v_{\text{cm}} = 0\] meaning the center of mass remains at rest according to the conservation of momentum.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Center of Mass
The center of mass is a point representing the average position of the entire mass of a system. For two objects, say a gun and a fired shot, it's like the balance point where both masses are distributed evenly. In our exercise, the gun and shot together form a system, and this system had no motion to begin with. So, initially, the center of mass of the system was at rest.

After the spring gun fires, the bullet moves one way and the gun moves slightly in the opposite direction. This counter movement ensures that the center of mass doesn't change position; it stays stationary. Why? Because there were no external forces added to change its position. So even after firing, the whole seesaw (center of mass) doesn't tilt but continues to balance at the same point in space.
Spring Gun System
A spring gun system is a setup where a spring-based gun discharges a projectile. The spring in the gun stores potential energy when compressed and releases it to propel the shot. This kind of system is perfect for illustrating concepts like conservation of energy and momentum.

In our scenario, the spring in the gun is loaded with potential energy, which is converted into kinetic energy when the shot is fired. The gun and the shot are part of the same system, and because the surface is frictionless, no outside horizontal forces disturb the motion. This isolation helps to better observe the momentum and energy transformation without complications.
Isolated System
An isolated system is one where no external forces act on it. Think of a spaceship floating in space; nothing from the outside pushes or pulls it. In the context of this exercise, the gun and shot are on a frictionless surface, which means there's no outside friction to slow them down. This setup forms an isolated system.

The beauty of an isolated system is that it allows us to use the conservation of linear momentum. No matter what happens inside — like a spring firing a bullet — the total momentum of the system remains constant. Initially, both the gun and shot are at rest, so their combined momentum is zero. When the shot is fired, any momentum the shot gains is exactly counteracted by the gun moving in the opposite direction.
Initial Momentum
Initial momentum refers to the momentum a system has before any events, like firing a shot, occur. In physics, momentum is the product of mass and velocity (\( p = mv \)), and it's a vector, meaning it has direction.

For our gun and shot system, since they were initially at rest on a frictionless surface, their initial momentum was zero. This is crucial because, according to the conservation of momentum, if no external forces are applied, the system's total momentum after an event must equal the initial momentum.

In this exercise, after the gun fires, both the gun and the bullet gain momentum. The bullet speeds off in one direction, but the gun recoils in the opposite direction. This balancing act ensures that the total momentum of the system remains zero, just as it was initially.

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