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A body of mass \(4 \mathrm{~kg}\) is moving with momentum of \(8 \mathrm{~kg}-\mathrm{ms}^{-1}\). A force of \(0.2 \mathrm{~N}\) acts on it in the direction of motion of the body for 10 s. The increase in kinetic energy in joule is (a) 10 (b) \(8.5\) (c) \(4.5\) (d) 4

Short Answer

Expert verified
The increase in kinetic energy is 4.5 Joules.

Step by step solution

01

Understand the Problem

We need to find the increase in kinetic energy of a body when a force is applied over a given time. We know the initial momentum and the force applied.
02

Calculate Initial Speed

We use the initial momentum to find the initial speed using the formula: \( \text{momentum} = m \cdot v \). Given momentum is 8 kg路ms鈦宦 and mass \( m = 4 \) kg, we have: \( 8 = 4 \cdot v \). Solve for \( v \): \( v = 2 \) m/s.
03

Calculate Acceleration

Use Newton's second law to find the acceleration: \( F = m \cdot a \). Given force \( F = 0.2 \) N and mass \( m = 4 \) kg, we have: \( 0.2 = 4 \cdot a \). Solve for \( a \): \( a = 0.05 \) m/s虏.
04

Find Final Speed

Use the equation of motion: \( v_f = v_i + a \cdot t \), where \( v_i = 2 \) m/s, \( a = 0.05 \) m/s虏, and \( t = 10 \) s. Thus, \( v_f = 2 + 0.05 \times 10 = 2.5 \) m/s.
05

Calculate Initial Kinetic Energy

The initial kinetic energy \( KE_i \) is given by \( \frac{1}{2} m v_i^2 \). Using \( m = 4 \) kg and \( v_i = 2 \) m/s, \( KE_i = \frac{1}{2} \times 4 \times 2^2 = 8 \) Joules.
06

Calculate Final Kinetic Energy

The final kinetic energy \( KE_f \) is given by \( \frac{1}{2} m v_f^2 \). Use \( m = 4 \) kg and \( v_f = 2.5 \) m/s, \( KE_f = \frac{1}{2} \times 4 \times (2.5)^2 = 12.5 \) Joules.
07

Calculate Increase in Kinetic Energy

The increase in kinetic energy is \( KE_f - KE_i = 12.5 - 8 = 4.5 \) Joules.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Momentum
When we talk about momentum, we are discussing how much motion an object has. It is simply determined by the product of an object's mass and velocity. In formulas, it is represented by \( p = m imes v \). Here, \( p \) stands for momentum, \( m \) for mass, and \( v \) is the velocity.

In the given exercise, a body of mass \( 4 \) kg is moving with a momentum of \( 8 \) kg路m/s. Given this information, we can calculate its initial velocity. We rearrange the momentum formula to \( v = \frac{p}{m} \) which gives us \( 2 \) m/s as the initial velocity. By understanding this, students can see how momentum directly relates mass and velocity, and how it is crucial in determining the starting speed of the object.

**Key Points**
  • Momentum is a measure of motion.
  • It is calculated as mass times velocity.
  • It plays a crucial role in determining the initial speed of an object.
Newton's Second Law
Newton's Second Law is fundamental in understanding how force affects the motion of an object. Simply put, it states that the force applied to an object is equal to the mass of the object times its acceleration. Mathematically, it is expressed as \( F = m imes a \).

In our scenario, a force of \( 0.2 \) N acts on a body with a mass of \( 4 \) kg. By applying Newton's Second Law, we can determine the acceleration produced by this force. Solving \( 0.2 = 4 \times a \), we find that the body accelerates at \( 0.05 \) m/s虏. This relationship helps explain how a small force over time can change the velocity of an object. Students often gain insight into how different amounts of force can affect motion, depending on the object's mass.

**Key Points**
  • Force is dependent on both mass and acceleration.
  • Even a small force over time can affect an object's speed.
  • Newton鈥檚 Second Law helps in understanding the cause of acceleration.
Equation of Motion
The equation of motion is crucial in relating velocity, acceleration, and time. It provides a straightforward way to calculate an object's final velocity when its initial velocity, acceleration, and the time period are known. The equation is \( v_f = v_i + a \times t \), where \( v_f \) is the final velocity, \( v_i \) is the initial velocity, \( a \) is the acceleration, and \( t \) is the time.

When solving the given problem, we begin with an initial velocity of \( 2 \) m/s. We calculate the final velocity after \( 10 \) seconds of acceleration at \( 0.05 \) m/s虏. By applying the motion equation, we find that the final velocity becomes \( 2.5 \) m/s. This formula helps students see how continuously applied force results in a gradual change in velocity.

**Key Points**
  • It connects velocity, acceleration, and time into one formula.
  • Provides a way to find the final speed.
  • Helps understand how velocity changes over time.
Initial and Final Velocity
Understanding initial and final velocity is key to analyzing the change in motion and energy of an object. Initial velocity is simply the speed of the object before any forces act upon it. In our scenario, this was calculated using momentum and was found to be \( 2 \) m/s.

The final velocity, on the other hand, results after the object has undergone acceleration for a certain period. We found this to be \( 2.5 \) m/s after a force acted on it for \( 10 \) seconds. These velocities help us calculate the change in kinetic energy鈥攁 measure of work done on the object.

**Key Points**
  • Initial velocity is the starting speed before forces act.
  • Final velocity is after experiencing acceleration.
  • Both are essential for calculating changes in kinetic energy.

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Most popular questions from this chapter

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The potential energy function for a particle executing linear SHM is given by \(V(x)=\frac{1}{2} k x^{2}\) where \(k\) is the force constant of the oscillator. For \(k=0.5 \mathrm{~N} / \mathrm{m}\), the graph of \(V(x)\) versus \(x\) is shown in the figure. A particle of total energy \(E\) turns back when it reaches \(x=\pm x_{m}\). If \(V\) and \(K\) indicate the \(\mathrm{PE}\) and \(\mathrm{KE}\) respectively of the particle at \(x=\pm x_{m}\) then which of the following is correct? \(\quad\) [NCERT Exemplar] (a) \(V=0, \bar{K}=\mathrm{E}\) (b) \(V=\mathrm{E}, \bar{K}=0\) (c) \(V

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