Chapter 7: Problem 43
A stone of mass \(2 \mathrm{~kg}\) is projected upward with kinetic energy of \(98 \mathrm{~J}\). The height at which the kinetic energy of the body becomes half its original value, is given by (Take \(g=10 \mathrm{~ms}^{-2}\) ) (a) \(5 \mathrm{~m}\) (b) \(2.5 \mathrm{~m}\) (c) \(1.5 \mathrm{~m}\) (d) \(0.5 \mathrm{~m}\)
Short Answer
Step by step solution
Identify Known Values
Understand Half Kinetic Energy
Use Energy Conservation Principle
Set up the Equation
Solve for Height
Select the Correct Option
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Conservation of Mechanical Energy
The formula governing this conservation is straightforward:
- Initial Energy: The total energy at the start (all kinetic at point of projection) = \( K_i = 98 \, \text{J} \).
- Final Energy: The energy becomes a combination of kinetic (\( K_f = 49 \, \text{J} \) in the problem) and potential energy when the stone is at a height \( h \).
- At any point, \( K_i = K_f + \Delta U \), where \( \Delta U \) is the change in potential energy.
- This conservation helps us calculate the height where kinetic energy becomes half by equating it to potential energy changes.
Potential Energy
The potential energy is determined by the formula:
- \( U = mgh \)
- where \( m \) is mass, \( g \) is the gravitational constant, and \( h \) is the height.
- Initial potential energy at the ground level is zero.
- At height \( h \), potential energy \( = mgh = 49 \, \text{J} \), using the values provided.
Projectile Motion
It involves two components:
- A vertical component affected by gravity.
- A horizontal component, often ignored for vertical-only problems such as this.
Key aspects of projectile motion include:
- The trajectory depends on the initial speed and angle.
- Gravitational force acts downward, slowing the rise and accelerating the fall.
- A perfect example of the conservation of energy is how potential and kinetic energies exchange roles.