Chapter 3: Problem 55
Three vectors \(\mathbf{A}, \mathbf{B}\) and \(\mathbf{C}\) satisfy the relation \(\mathbf{A B}=0\) and \(\mathbf{A C}=0 .\) If \(\mathbf{B}\) and \(\mathbf{C}\) are not lying in the same plane, then \(\mathbf{A}\) is parallel to (a) \(\mathrm{B}\) (b) \(\mathrm{C}\) (c) \(\mathrm{B} \times \mathrm{C}\) (d) \(\mathrm{BC}\)
Short Answer
Step by step solution
Understanding the Problem
Analyzing Dot Product Implications
Vectors and Plane Formulation
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Dot Product
- \( \mathbf{A} \cdot \mathbf{B} = |\mathbf{A}| |\mathbf{B}| \cos(\theta) \)
If \( \cos\theta \) is zero, then \( \theta \) must be \(90^\circ\), indicating the vectors are perpendicular.
In this exercise, since \( \mathbf{A} \cdot \mathbf{B} = 0 \) and \( \mathbf{A} \cdot \mathbf{C} = 0 \), \( \mathbf{A} \) is perpendicular to both \( \mathbf{B} \) and \( \mathbf{C} \). This is crucial for understanding vector relationships in three-dimensional space.
Cross Product
Unlike the dot product, the result of a cross product is a vector, not a scalar.
The magnitude of the cross product follows:
- \( |\mathbf{B} \times \mathbf{C}| = |\mathbf{B}| |\mathbf{C}| \sin(\theta) \)
This vector is perpendicular to the plane formed by \( \mathbf{B} \) and \( \mathbf{C} \). In our context, since \( \mathbf{A} \) is parallel to the cross product \( \mathbf{B} \times \mathbf{C} \), it means \( \mathbf{A} \) is orthogonal to the plane which \( \mathbf{B} \) and \( \mathbf{C} \) form.
Orthogonality
To determine orthogonality, the dot product between the two vectors must be zero. This is a crucial condition and is applied in various areas, such as determining perpendicular directions in geometry or in optimizing equations in mathematics.
In our scenario, since \( \mathbf{A} \cdot \mathbf{B} = 0 \) and \( \mathbf{A} \cdot \mathbf{C} = 0 \), \( \mathbf{A} \) is orthogonal to both \( \mathbf{B} \) and \( \mathbf{C} \).
Recognizing this helps in understanding why \( \mathbf{A} \) must lie along the direction normal to the plane created by \( \mathbf{B} \) and \( \mathbf{C} \).
Linear Independence
If two vectors are not in the same plane, they are linearly independent, meaning one vector cannot be expressed as a scalar multiple of the other.
In vector algebra, this implies that these vectors span a plane in three-dimensional space. When \( \mathbf{B} \) and \( \mathbf{C} \) are linearly independent, they define a unique plane.
For this exercise, the linear independence of \( \mathbf{B} \) and \( \mathbf{C} \) ensures the existence of a non-zero vector \( \mathbf{B} \times \mathbf{C} \) that is perpendicular to this plane, aligning perfectly with the perpendicular vector \( \mathbf{A} \).
Understanding linear independence assists in distinguishing between vectors in the same plane and those spanning or orthogonal to a plane.