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In a \(n-p-n\) transistor circuit, the collector current is \(10 \mathrm{~mA}\). If 95 percent of the electrons emitted reach the collector, which of the following statements are true? (a) The emitter current will be \(8 \mathrm{~mA}\) (b) The emitter current will be \(10.53 \mathrm{~mA}\) (c) The base current will be \(5.53 \mathrm{~mA}\) (d) The base current will be \(2 \mathrm{~mA}\)

Short Answer

Expert verified
The emitter current is 10.53 mA; thus, option (b) is true.

Step by step solution

01

Understanding the Problem

We know that in an n-p-n transistor circuit, the collector current \(I_c\), the base current \(I_b\), and the emitter current \(I_e\) are related by the equation: \(I_e = I_c + I_b\). We're given that \(I_c = 10 \mathrm{~mA}\) and that 95% of electrons emitted by the emitter reach the collector.
02

Calculate Emitter Current

You are given that 95% of the emitter current \(I_e\) equals the collector current \(I_c\). Therefore, \(I_e = \frac{100}{95} \times I_c\). Given \(I_c = 10 \mathrm{~mA}\), we calculate \(I_e = \frac{100}{95} \times 10 = 10.53 \mathrm{~mA}\).
03

Calculate Base Current

Using the relation \(I_e = I_c + I_b\), and knowing \(I_c = 10 \mathrm{~mA}\) and the calculated \(I_e = 10.53 \mathrm{~mA}\), we find the base current: \(I_b = I_e - I_c = 10.53 - 10 = 0.53 \mathrm{~mA}\).
04

Determine True Statements

With \(I_e = 10.53 \mathrm{~mA}\) and \(I_b = 0.53 \mathrm{~mA}\), we can now evaluate the given statements: - (a) False, because \(I_e = 10.53 \mathrm{~mA}\).- (b) True, because this matches our calculated \(I_e\).- (c) False, because \(I_b = 0.53 \mathrm{~mA}\).- (d) False, because \(I_b = 0.53 \mathrm{~mA}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

n-p-n Transistor
An n-p-n transistor is a type of bipolar junction transistor (BJT) that consists of two n-type semiconductor materials separated by a p-type material. It functions as a current amplifier and is primarily used in switching and amplification applications. The key feature of an n-p-n transistor is its three layers: the emitter, base, and collector.
  • **Emitter:** It is heavily doped to ensure the efficient injection of charge carriers (electrons in n-p-n) into the base.
  • **Base:** This layer is lightly doped and thin, allowing electrons to move from the emitter to the collector with minimal recombination.
  • **Collector:** It is moderately doped and collects electrons transferred through the base, playing a vital role in the transistor's function.
In operation, the emitter injects electrons into the base, which controls the number of electrons forwarded to the collector. This controlled flow allows for amplification and switching capabilities.
Emitter Current Calculation
In an n-p-n transistor, the emitter current ( \(I_e\)) is the total current that flows from the emitter. It includes both the base and collector currents. Calculating the emitter current involves understanding how the collector current ( \(I_c\)) and base current ( \(I_b\)) relate. Given that 95% of the electrons emitted from the emitter reach the collector, we use this ratio to determine the total emitter current:\[I_e = \frac{100}{95} \times I_c\]For example, with a collector current of 10 mA,\[I_e = \frac{100}{95} \times 10 = 10.53 \mathrm{~mA}\]This formula shows how the efficiency of the electron transfer influences the emitter current. Understanding the relationship between these currents is crucial for designing and analyzing circuits with transistors.
Collector Current
The collector current ( \(I_c\)) in an n-p-n transistor is the current flowing through the collector, primarily consisting of electrons that have passed through the base. In our exercise, the collector current is given as 10 mA.The collector current is typically the largest current in the transistor and is crucial for determining the transistor's functioning. It plays a central role in amplifying the input signal:
  • Since the collector voltage is usually higher than the base voltage, it attracts the electrons.
  • The efficiency depends on how many of the charge carriers injected by the emitter are effectively collected.
The concept of collector efficiency, where 95% of emitted electrons are collected, helps determine the relationship between the emitter and collector currents. This understanding is fundamental for designing electronics that rely on precise current control.
Base Current Calculation
The base current ( \(I_b\)) in an n-p-n transistor is a smaller current that serves to control the larger collector current. It flows through the base terminal and is pivotal in regulating the transistor's operation.Using the relationship:\[I_e = I_c + I_b\]We can find the base current:\[I_b = I_e - I_c\]With the calculated emitter current of 10.53 mA and a collector current of 10 mA, the base current is:\[I_b = 10.53 - 10 = 0.53 \mathrm{~mA}\]This calculation shows how a relatively small base current can control a much larger collector current, highlighting the transistor's role as a current amplifier. Understanding this relationship is crucial for effectively utilizing transistors in electronic circuits.

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