Chapter 26: Problem 41
The transfer ratio of the transistor is 50 . The input resistance of the transistor when used in the CE configuration is \(1 \mathrm{k} \Omega\). The peak value for an AC input voltage of \(0.01 \mathrm{~V}\) of collector current is (a) \(500 \mu \mathrm{A}\) (b) \(0.25 \mathrm{~mA}\) (c) \(400 \mathrm{~mA}\) (d) \(0.01 \mathrm{~mA}\)
Short Answer
Step by step solution
Understand the Problem
Calculate Input Current
Calculate Collector Current
Verify the Given Options
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ohm's Law
- \( V \) stands for voltage, which is the potential difference across the component,
- \( I \) represents the current flowing through the component,
- and \( R \) is the resistance that opposes the flow of current.
Current Gain
Common-Emitter Configuration
- The base-emitter junction is forward-biased.
- The collector-base junction is reverse-biased.
Input Resistance
- Related to the impedance matching in circuit design.
- Critical for minimizing signal loss.
- Helps in determining the efficiency of signal transfer from one stage to the next.