Chapter 25: Problem 53
An electron of mass \(m\) and charge \(e\) initially at rest gets accelerated by a constant electric field \(E\). The rate of change of de-Broglie wavelength of this electron at time \(t\) ignoring relativistic effect is (a) \(\frac{-h}{e E t^{2}}\) (b) \(\frac{-e E t}{E}\) (c) \(\frac{-m h}{e E t^{2}}\) (d) \(\frac{-h}{e E}\)
Short Answer
Step by step solution
Understand the de-Broglie Wavelength
Determine the Momentum of the Electron
Differentiate the de-Broglie Wavelength with Respect to Time
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Electron Momentum
- Momentum (\( p \)) = mass (\( m \)) * velocity (\( v \))
- Momentum (\( p \)) = charge (\( e \)) * electric field (\( E \)) * time (\( t \))
Electric Field
- Force (\( F \)) = charge (\( e \)) * electric field (\( E \))
Rate of Change
- De-Broglie wavelength (\( \lambda \)) = \( \frac{h}{p} \)
Planck's Constant
- De-Broglie wavelength (\( \lambda \)) equation: \( \lambda = \frac{h}{p} \)