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An object is approaching a plane mirror at \(10 \mathrm{cms}^{-1} .\) A stationary observer sees the image. At what speed will the image approach the stationary observer? (a) \(10 \mathrm{cms}\) (b) \(5 \mathrm{cms}^{-1}\) (c) \(20 \mathrm{cms}^{-1}\) (d) \(15 \mathrm{cms}^{-1}\)

Short Answer

Expert verified
(c) \(20 \, \text{cm/s}\)

Step by step solution

01

Understand the Concept

The image in a plane mirror appears to be behind the mirror at the same distance as the object in front. As the object moves towards the mirror, the image also moves towards the mirror at the same rate relative to the mirror.
02

Calculate the Speed of Image Relative to Mirror

Since the object is approaching the mirror at a speed of \(10 \, \text{cm/s}\), the image will move towards the mirror at a speed of \(10 \, \text{cm/s}\) relative to the mirror.
03

Calculate the Speed of Image Relative to Observer

For a stationary observer, the image appears to move towards them at twice the speed of the object, as both the object and image are closing in on the observer from both sides. Therefore, the image approaches the observer at \(20 \, \text{cm/s}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Plane Mirror
A plane mirror is a flat reflective surface. Unlike curved mirrors, plane mirrors do not distort the image they reflect. They create images of objects placed in front of them that seem to appear "behind" the mirror at the same distance as the object is in front. This means that if you are standing one meter away from a mirror, it looks like your reflection is one meter behind the mirror.
Plane mirrors are commonly used in everyday life, like in bathrooms and dressing rooms, because they accurately represent how objects appear in reality. They reflect light according to the simple law of reflection, meaning the angle at which light comes in is equal to the angle at which it reflects off. This is called the angle of incidence equaling the angle of reflection.
Image Formation
The process of image formation in a plane mirror is straightforward and relies on basic geometric principles. When light rays hit a plane mirror, they reflect off the surface such that the angle of incidence is equal to the angle of reflection.
  • First, light travels from the object to the mirror.
  • It then gets reflected and travels to the observer’s eyes.
This reflection makes the brain think that the light is coming from a point behind the mirror, creating a virtual image which means the image appears to be behind the mirror. The image formed by a plane mirror is:
  • Upright and the same size as the object.
  • Reversed from left to right (laterally inverted).
  • Virtual, meaning it can't be projected onto a screen as it can't actually touch it.
For example, your left hand appears as the right hand in a mirror due to this lateral inversion.
Relative Motion
Relative motion refers to the movement of objects as observed from a specific frame of reference. In the context of mirrors and image formation, it’s vital to realize that both the object and its image have relative speeds that need to be considered.
Consider an object moving towards a plane mirror. From the mirror's perspective (its reference frame), both the object and its image are moving closer at the same speed. Imagine you are standing still, and an object approaches the mirror at a speed of 10 cm/s. The image in the mirror would appear to move at the same rate towards the mirror. However, from your perspective as a stationary observer, the image comes towards you at twice the speed of the object, because: - For every bit the object moves towards the mirror, the image moves the same distance toward the mirror but in the opposite direction from behind. - Thus, you would measure the image approaching you at 20 cm/s, doubling the speed of the object's movement.
Reflection
Reflection is the bouncing back of light rays when they hit a surface. The law of reflection governs this process, and it's the foundation behind how mirrors work. According to this law, the angle at which the incoming light hits a surface (the angle of incidence) is equal to the angle at which it leaves the surface (the angle of reflection).
In a plane mirror: - Light rays coming from an object strike the mirror and reflect back into the observer's eyes. - This repeated reflection is what gives us the ability to see images in mirrors, create symmetry, and learn spatial orientation. - If an object moves, the reflected light also changes direction and speed, which is how we perceive changes in image position or motion.
Understanding reflection helps us grasp how velocity of an image can be calculated relative to an observer, as seen in the mirror-related scenarios. These reflections allow users to perceive and interact with their environment, thanks to how light and mirrors play tricks on distance and direction.

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Most popular questions from this chapter

One of the refracting surfaces of a prism of angle \(30^{\circ}\) is silvered. A ray of light incident at an angle of \(60^{\circ}\) retraces its path. The refractive index of the material of prism is (a) \(\sqrt{3}\) (b) \(3 / 2\) (c) 2 (d) \(\sqrt{2}\)

When an object is kept at a distance of \(30 \mathrm{~cm}\) from a concave mirror, the image is formed at a distance of \(10 \mathrm{~cm}\). If the object is moved with a speed of \(9 \mathrm{~ms}^{-1}\), the speed with which images moves, is (a) \(0.1 \mathrm{~ms}^{-1}\) (b) \(1 \mathrm{~ms}^{-1}\) (c) \(3 \mathrm{~ms}^{-1}\) (d) \(9 \mathrm{~ms}^{-1}\)

A car is moving with at a constant speed of \(60 \mathrm{kmh}^{-1}\) on a straight road. Looking at the rear view mirror, the driver finds that the car following him is at distance of \(100 \mathrm{~m}\) and is approaching with a speed of \(5 \mathrm{~km} \mathrm{~h}^{-1}\). In order to keep track of the car in the rear, the driver begins to glance alternatively at the rear and side mirror of his car after every \(2 \mathrm{~s}\) till the other car overtakes. If the two cars were maintaining their speeds, which of the following statement (s) is/are correct? (a) The speed of the car in the rear is \(65 \mathrm{~km} \mathrm{~h}^{-1}\) (b) In the side mirror the car in the rear would appear to approach with a speed of \(5 \mathrm{~km} \mathrm{~h}^{-1}\) to the driver of the leading car (c) In the rear view minor, the speed of the approaching car would appeat to decrease as the distance between the. cars decreases (d) In the side mirror, the speed of the approaching car would appear to increase as the distance between the cars decreases

A thin lens has focal length, \(f_{1}\) and its aparture has diameter \(d\). It forms an image of intensity \(I .\) Now the central part of the aparture upto diameter \(\frac{d}{2}\) is blocked by an opaque paper. The focal length and image intensity will be change to (a) \(f\) and \(\frac{1}{4}\) (b) \(f\) and \(\frac{3 l}{4}\) (c) \(\frac{f}{2} \operatorname{and} \frac{l}{2}\) (d) \(\frac{3 f}{4}\) and \(\frac{1}{2}\)

A thin equiconvex lens of refractive index \(3 / 2\) and radius of curvature \(30 \mathrm{~m}\) is put in water (refractive index \(=\frac{4}{3}\). Its focal length is (a) \(0.15 \mathrm{~m}\) (b) \(0.30 \mathrm{~m}\) (c) \(0.45 \mathrm{~m}\) (d) \(1.20 \mathrm{~m}\)

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