Chapter 22: Problem 66
The radiowave (wave length \(21 \mathrm{~cm}\) ) is emitted by hydrogen in inter stellar space is due to the interaction called the hyperfine interaction in atomic hydrogen, the energy of the emitted wave is nearly [NCERT] (a) \(\left.10^{-17}\right\rfloor\) (b) \(1 \mathrm{~J}\) (c) \(7 \times 10^{-4} \mathrm{~J}\) (d) \(10^{-14} \mathrm{~J}\)
Short Answer
Step by step solution
Understand the Problem
Recall the Energy-Wavelength Relationship
Identify Constants
Convert Units
Calculate Energy
Simplify the Calculation
Match with Options
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Atomic Hydrogen
Energy-Wavelength Relationship
- For long wavelengths like radiowaves, the energy is relatively low compared to shorter wavelengths like ultraviolet rays.
- The formula is crucial in fields such as astrophysics, allowing scientists to calculate the energy of light emissions from distant stars and galaxies based on their wavelength.
Planck's Constant
- It was introduced by Max Planck as part of his solution to the blackbody radiation problem, which was a big puzzle in physics at the beginning of the 20th century.
- Planck's constant plays a key role in the energy-wavelength relationship, serving as the proportionality constant in the equation \( E = hf \), where \( f \) is the frequency of the photon.
Radiowave Emission
- This emission is important in astronomy as it allows scientists to map hydrogen distribution in the galaxy, shedding light on the structure and dynamics of the Milky Way.
- The emissions result from hyperfine transitions between different energy states of atomic hydrogen due to the magnetic interaction within the atom.