Chapter 21: Problem 34
What is the self-inductance of an air core solenoid \(1 \mathrm{~m}\) long, diameter \(0.05 \mathrm{~m}\), if it has 500 turns? Take \(\pi^{2}=10\) (a) \(3.15 \times 10^{-4} \mathrm{H}\) (b) \(4.8 \times 10^{-4} \mathrm{H}\) (c) \(5 \times 10^{-4} \mathrm{H}\) (d) \(6.25 \times 10^{-4} \mathrm{H}\)
Short Answer
Step by step solution
Understanding the Formula
Calculating the Cross-sectional Area
Compute the Area Result
Substitute and Simplify
Calculate the Numerical Result
Convert to Standard Form
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Air Core Solenoid
This kind of solenoid is best when high-frequency applications are involved because it doesn't suffer from the magnetic losses seen in iron-core solenoids.
While its inductance may be lower than that of a solenoid with a core, the linearity and other properties make it highly valuable in circuits where minimal distortion is crucial.
- Air core solenoids are lightweight, because they don't have a heavy core.
- They offer stability in reacting to changes in electrical current.
- The inductance varies linearly with the number of turns in the coil and the coil's geometry.
Cross-Sectional Area of Solenoid
For instance, a solenoid with a diameter of \(0.05 \ \mathrm{m}\) would have a cross-sectional area calculated as follows:
- First, take half of the diameter: \(\frac{0.05}{2} = 0.025 \ \mathrm{m}\).
- Then, square this value: \(0.025^2 = 0.000625 \ \mathrm{m^2}\).
- Multiply by \(\pi\) (approximately \(3.14\) or \(\pi^2 = 10\)) to get the area: \(A = 10 \times 0.000625 = 0.00625 \ \mathrm{m^2}\).
Permeability of Free Space
In the formula for the self-inductance of a solenoid, namely \( L = \frac{\mu_0 N^2 A}{l} \), \(\mu_0\) is used to calculate the magnetic field strength that the solenoid can produce.
The value of the permeability of free space is approximately \(4\pi \times 10^{-7} \ \mathrm{H/m}\). This fundamental constant is used because it simplifies the mathematical expressions involved in electromagnetism. Here are some important points about \(\mu_0\):
- It is a universal constant, which means it's the same everywhere in the universe under normal conditions.
- It relates to how much resistance is encountered when forming a magnetic field in a vacuum.
- As \(\mu_0\) is constant, changes in the solenoid's inductance primarily arise from alterations to the coil's physical characteristics, like its area or number of turns.