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The horizontal component of flux density of earth's magnetic field is \(1.7 \times 10^{-5} \mathrm{~T}\). The value of horizontal component of intensity of earth's magnetic field will be (a) \(24.5 \mathrm{Am}^{-1}\) (b) \(13.5 \mathrm{Am}^{-1}\) (c) \(1.53 \mathrm{Am}^{-1}\) (d) \(0.35 \mathrm{Am}^{-1}\)

Short Answer

Expert verified
The answer is option (b) \(13.5 \mathrm{Am}^{-1}\).

Step by step solution

01

Understanding the Problem

We are given the horizontal component of the Earth's magnetic flux density, which is denoted as \(B_h = 1.7 \times 10^{-5} \mathrm{~T}\). We need to find the horizontal component of the intensity of Earth's magnetic field and compare it to the given options.
02

Formula for Magnetic Field Intensity

The relationship between magnetic flux density \(B\) and magnetic field intensity \(H\) is given by the formula \(B = \mu H\), where \(\mu\) is the permeability of the medium, for vacuum or air \(\mu_0 = 4\pi \times 10^{-7} \mathrm{~Tm/A}\). We are dealing with air, so we use \(\mu_0\).
03

Solve for H

To find \(H\), we rearrange the formula: \(H = \frac{B_h}{\mu_0}\). Substituting the values, we have:\[ H = \frac{1.7 \times 10^{-5}}{4\pi \times 10^{-7}} \]
04

Calculate the Value of H

Now perform the calculation:\[ H = \frac{1.7 \times 10^{-5}}{4\pi \times 10^{-7}} \approx \frac{1.7 \times 10^{-5}}{1.25664 \times 10^{-6}} \]\[ H \approx 13.5 \mathrm{Am}^{-1}\]
05

Choose the Correct Option

By comparing the calculated value, \(13.5 \mathrm{Am}^{-1}\), with the given options, we select option (b) as it matches our result.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Flux Density
Magnetic flux density, often symbolized as \(B\), describes how strong a magnetic field is at a certain point in space. It is measured in Tesla (\(T\)) and tells us about the concentration of magnetic lines of force (also called magnetic field lines) in a given area. A larger magnetic flux density means more magnetic field lines are passing through that area. This is crucial in determining how a material will respond to a magnetic force.

When we talk about the Earth, the magnetic flux density is all around us, and it helps us understand how things like compasses work, as they rely on the Earth's magnetic field.
  • The Earth's overall magnetic field is complex and varies both with location and time.
  • We use the magnetic flux density to help measure parts of this field, like the horizontal component given in exercises like the one we've discussed.
The horizontal component of the Earth's magnetic flux density helps in navigation and determining the magnetic North-South directions used in compasses and aeronautics.
Magnetic Field Intensity
Magnetic field intensity, denoted by \(H\), gives us a measure of the strength of a magnetic field from the source of the field itself, independent of the material surrounding it. It's measured in ampere per meter (\(Am^{-1}\)).

While magnetic flux density tells us about the concentration of field lines, magnetic field intensity is more about the cause of the field. It's like saying, "How strong is the magnetic force being applied?"
  • This concept is crucial when analyzing how different materials react when placed in a magnetic field. For instance, materials like iron can intensify magnetic fields significantly.
  • The exercise presented involves calculating \(H\) from the known magnetic flux density \(B\) using the relationship \(B = \mu H\).
Once we have the value of \(H\), we can better understand the magnetic properties and effects in that specific location or medium.
Permeability
Permeability is a concept that describes how well a material can support the formation of a magnetic field within itself. It is represented by \(\mu\) and is key to solving problems involving magnetic fields.
  • The basic permeability of free space, also known as the permeability of vacuum, is denoted by \(\mu_0\). Its value is a constant \(4\pi \times 10^{-7} \mathrm{Tm/A}\).
  • This constant is important in equations like \(B = \mu H\), where the permeability helps determine the magnetic field intensity given a certain magnetic flux density.
In the exercise, since we're dealing with air, which behaves similarly to a vacuum in many scenarios, we use \(\mu_0\). By substituting \(\mu_0\) into the equation, we're able to solve for the magnetic field intensity \(H\), demonstrating how permeability plays an essential role in magnetic field calculations.

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Most popular questions from this chapter

A bar magnet \(20 \mathrm{~cm}\) in length is placed with its south pole towards geographie north. 'The neutral points are situated at a distance of \(40 \mathrm{~cm}\) from centre of the magnet. If horizontal component of earth's field \(3.2 \times 10^{-5} \mathrm{~T}\), then pole strength of magnet is (a) \(5 \mathrm{Am}\) (b) \(10 \mathrm{Am}\) (c) \(45 \mathrm{Am}\) (d) 20 Am

A steel wire of length \(l\) has a magnetic moment \(M\). It is bent at its middle point at an angle of \(60^{\circ} .\) Then the magnetie moment of new shape of wire will be (a) \(M / \sqrt{2}\) (b] \(M / 2\) (c) \(M\) (d) \(\sqrt{2} M\)

A magnetic needle suspended by a silk thread is vibrating in the earth's magnetie field, if the temperature of the needle is increased by \(500^{\circ} \mathrm{C}\), then [BVP Engg. 2006] (a) the time period decreases (b) the time period remains unchanged (c) the time period increases (d) the needle stops vibrating

At the magnetic north pole of the earth, the value of the horizontal component of earth's magnetic field and angle of dip are respectively (a) zero, maximum (b) maximum, minimum (c) maximum, maximum (d) minimum, minimum

A long solenoid has 1000 turs per metre and carries a current of \(1 \mathrm{~A}\). It has a soft iron core of \(\mu_{r}=1000\). The core is heated beyond the Curie temperature \(T_{e}\). INCERT Exemplar] (a) The H field in the solenoid is (nearly) unchanged but the B field decreases drastically (b) The \(\mathrm{H}\) and \(\mathrm{B}\) fields in the solenoid are nearly unchanged (c) The magnetisation in the core reverses direction (d) The magnetisation in the core diminishes by a factor of ahout \(10^{1}\)

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