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A toroid of \(n\) turns, mean radius \(R\) and cross-sectional radius a carries current \(I\). It is placed on a horizontal table taken as \(x-y\) plane. Its magnetic moment \(\mathbf{m} \quad\) [NCERT Exemplar] (a) is non-zero and points in the z-direction by symmetry (b) points along the axis of the toroid \((\mathrm{m}=\mathrm{m}\) ) (c) is zero, otherwise there would be a field falling as \(\frac{1}{r^{3}}\) at large distances outside the toroid (d) is pointing radially outwards

Short Answer

Expert verified
(a) The magnetic moment is non-zero and points in the z-direction by symmetry.

Step by step solution

01

Understand the Magnetic Moment of a Current Loop

A toroid can be seen as a solenoid (coil of wire) that has been bent into a circular shape, forming a continuous loop. The magnetic moment \( \mathbf{m} \) of a current loop is given by: \( \mathbf{m} = nIA \), where \( n \) is the number of turns, \( I \) is the current, and \( A \) is the area of the loop. The direction of \( \mathbf{m} \) is determined by the right-hand grip rule: if the fingers of the right hand curl in the direction of the current, the thumb points in the direction of \( \mathbf{m} \).
02

Analyze Symmetry and Direction of Magnetic Moment

The symmetry of the toroid dictates its magnetic moment. Since the toroid is symmetric and forms a loop in the \(x-y\) plane, the resulting magnetic moment \( \mathbf{m} \) will point perpendicular to this plane. According to the right-hand rule, the magnetic moment will point in the \( z \) direction, perpendicular to the plane of the toroid.
03

Address the Presence of External Magnetic Field

One of the important characteristics of a toroid is that it confines the magnetic field inside, leading to no external magnetic field at large distances. This means that the external magnetic field due to the toroid falls off more rapidly than \( \frac{1}{r^3} \), approximately to zero outside the toroid loop.
04

Choose the Correct Option

Considering the characteristics of the magnetic moment, its direction, and the behavior of the magnetic field around the toroid, we can conclude that option (a) is correct: "The magnetic moment is non-zero and points in the \( z \)-direction by symmetry."

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Current Loop in a Toroid
A toroid is an interesting structure that combines the principles of a current loop and magnetic fields. Imagine a solenoid, which is essentially a coil of wire, bent into a donut shape, making it a circular loop—this forms a toroid. The concept of a current loop is fundamental to understanding how the magnetic moment arises in such a structure. When a current follows the circular path of the toroid, each turn of wire contributes to the overall magnetic effect. The magnetic moment \( \mathbf{m} \) is an important measure in this context. It tells us about the strength and direction of the magnetic field produced by this loop. The magnitude of the magnetic moment in a current loop is given by \( \mathbf{m} = nIA \), where \( n \) represents the number of turns in the coil, \( I \) is the current flowing through the wire, and \( A \) is the area of the loop formed by the coil.
  • More turns mean a larger magnetic moment.
  • Higher current results in a stronger magnetic field.
In a toroid, the current follows a continuous loop, enhancing the magnetic field produced within.
Applying the Right-Hand Rule
The right-hand rule is a nifty tool that helps to determine the direction of the magnetic moment and the magnetic field lines. When dealing with a toroid or any current loop, this rule comes in handy to visualize the 3D orientation of these vectors.Here's how to employ the right-hand rule for a current loop:
  • Curl the fingers of your right hand in the direction of the current flowing through the toroid.
  • Your thumb will then point in the direction of the magnetic moment \( \mathbf{m} \).
For a toroid lying flat in the \( x-y \) plane, the right-hand rule tells us that the magnetic moment is directed along the \( z \) axis. This is because any planar loop formation creates a magnetic moment perpendicular to that plane. This rule underscores a visual intuition about magnetic effects and reinforces the connection between current direction and magnetic moment orientation.
Exploring Symmetry in Magnetic Fields of a Toroid
Symmetry is a key feature in determining how magnetic fields behave, especially in a toroid. Because the toroid forms a perfect loop in the \( x-y \) plane, we expect its properties, such as the magnetic moment, to be uniform and symmetric.In magnetic field theory, this symmetry means:
  • The magnetic moment \( \mathbf{m} \) points perpendicular to the plane, in the \( z \)-direction.
  • The magnetic field is confined within the core of the toroid, resulting in negligible external magnetic fields at distances outside the toroid.
This symmetry ensures that the toroid doesn’t create significant external magnetic fields, and thus, the field outside falls off faster than \( 1/r^3 \). This unique property of toroids is why they are widely used in applications requiring magnetic field confinement, such as transformers and inductors.

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Most popular questions from this chapter

A long solenoid has 1000 turs per metre and carries a current of \(1 \mathrm{~A}\). It has a soft iron core of \(\mu_{r}=1000\). The core is heated beyond the Curie temperature \(T_{e}\). INCERT Exemplar] (a) The H field in the solenoid is (nearly) unchanged but the B field decreases drastically (b) The \(\mathrm{H}\) and \(\mathrm{B}\) fields in the solenoid are nearly unchanged (c) The magnetisation in the core reverses direction (d) The magnetisation in the core diminishes by a factor of ahout \(10^{1}\)

A magnetie needle lying parallel to a magnetic field required \(W\) units of work to turn it through \(60^{\circ} .\) The torque required to maintain the needle in this position will be (a) \(\sqrt{3} w\) (b) \(W\) (c) \(\sqrt{3} \frac{W}{2}\) (d) \(2 \mathrm{~W}\)

A bar magnet of length \(3 \mathrm{~cm}\) has a point \(A\) and \(B\) along axis at a distance of \(24 \mathrm{~cm}\) and \(48 \mathrm{~cm}\) on the opposite ends. Ratio of magnetic fields at these points will be (a) 8 (b) 3 [c) 4 idi \(1 / 2 \sqrt{2}\)

\(S\) is the surface of a lump of magnetic material. INCERT Exemplar] (a) Lines of B are necessarily continuous across 5 (b) Some lines of B must be discontinuous across 5 (c) Lines of \(\mathrm{H}\) are necessarily continuous across \(\mathrm{S}\) (d) Lines of \(\mathrm{H}\) cannot all be continuous across \(S\)

Two short bar magnets of length \(1 \mathrm{~cm}\) each have magnetic moments \(1.20 \mathrm{Am}^{2}\) and \(1.00 \mathrm{Am}^{2}\) respectively. They are placed on a horizontal table parallel to each other with their \(N\) poles pointing towards the south. They have a common magnetic equator and are separated by a distance of \(20.0 \mathrm{~cm}\). The value of the resultant horizontal magnetic induction at the mid-point \(O\) of the line joining their centres is elose to (Horizontal component of the earth's magnetic induction is \(3.6 \times 10^{-5} \mathrm{~Wb} / \mathrm{m}^{2}\) ) IJEE Main 2013| (a) \(3.6 \times 10^{-5} \mathrm{~Wb} / \mathrm{m}^{2}\) (b) \(2.56 \times 10^{-4} \mathrm{~Wb} / \mathrm{m}^{2}\) (c) \(3.50 \times 10^{-4} \mathrm{~Wb} / \mathrm{m}^{2}\) (d) \(5.80 \times 10^{-4} \mathrm{~Wb} / \mathrm{m}^{2}\)

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