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A particle starting from rest falls from a certain height. Assuming that the value of acceleration due to gravity remains the same throughout motion, its displacements in three successive half second intervals are \(S_{1}, S_{2}, S_{3} .\) Then, (a) \(S_{1}: S_{2}: S_{3}=1: 5: 9 \quad\) (b) \(S_{1}: S_{2}: S_{3}=1: 2: 3\) (c) \(S_{1}: S_{2}: S_{3}=1: 1: 1\) (d) \(S_{1}: S_{2}: S_{3}=1: 3: 5\)

Short Answer

Expert verified
Option (d) \(S_1 : S_2 : S_3 = 1:3:5\).

Step by step solution

01

Understanding the Problem

To solve the problem, we need to find the ratio of displacements in three successive half-second intervals for a particle falling from rest under uniform acceleration due to gravity, denoted as \(g\). The displacements are expressed as \(S_1\), \(S_2\), and \(S_3\).
02

Applying Kinematics Equation

The displacement \(S\) in a given interval, for a particle effectively starting from rest at the beginning of the interval, is given by \(S = ut + \frac{1}{2} a t^2\). Here, \(u = 0\), \(a = g\), and \(t = 0.5\,\text{s}\) for each interval.
03

Calculate First Interval Displacement \(S_1\)

Substitute \(t = 0.5\,\text{s}\) into the equation \(S_1 = \frac{1}{2} \cdot g \cdot (0.5)^2\). This simplifies to \(S_1 = \frac{1}{2} \cdot g \cdot 0.25 = \frac{1}{8} g\).
04

Calculate Second Interval Displacement \(S_2\)

For \(S_2\), the particle has fallen \(S_1\) in the first half-second. In the next half-second, it covers an additional distance: \(S_2 = 1g\cdot0.25\). Thus, \(S_2 = \frac{3}{8} g - \frac{1}{8} g = \frac{1}{2} g\).
05

Calculate Third Interval Displacement \(S_3\)

During the third half-second, calculate the total displacement up to this point using: \(displacement = 0.5g + \text{previous displacement} \). So, \(S_3 = \frac{9}{8} g - \frac{3}{8} g = \frac{3}{4} g\).
06

Determine the Ratio

Using the calculated values \(S_1 = \frac{1}{8} g\), \(S_2 = \frac{1}{2} g\), \(S_3 = \frac{3}{4} g\), we find the ratio \(S_1 : S_2 : S_3\) by simplifying \( \frac{1}{8} : \frac{3}{8} : \frac{5}{8}\) such that: \(S_1 : S_2 : S_3 = 1:3:5\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Uniform Acceleration
Uniform acceleration is a very important concept in physics, especially when studying motion. It describes a situation where an object's acceleration remains constant over time. In simpler terms, the velocity of the object is increasing or decreasing by the same amount every second.
This concept is vital for solving kinematics problems because it allows us to apply certain equations that predict an object's motion, such as the displacement over time.
In the exercise given, the particle is experiencing uniform acceleration, because it is falling due to gravity. This means its velocity will increase at a consistent rate in each time interval.
  • The uniform acceleration ensures that the derived equations remain valid and that solutions can be found using straightforward calculations.
  • This assumption simplifies our mathematical modeling since we don't have to deal with changing accelerations or additional forces acting on the particle.
Displacement Ratios
Displacement ratios help describe the relative distances covered in different time intervals when an object is in motion. In our exercise, these are the displacement distances covered by the falling object in successive half-second increments.
The use of displacement ratios allows us to compare these distances directly by expressing one as a multiple of the other. This can simplify complex problems into straightforward comparisons.
In our specific example, by calculating the displacements \( S_1, S_2, S_3 \) individually and then comparing them, we achieved the ratio \( 1:3:5 \).
  • This ratio indicates that the particle covers increasingly greater distances in each successive time interval.
  • Understanding displacement ratios is crucial in physics as it gives a clear picture of an object's motion over a period, without diving too deeply into complex mathematical derivations.
Acceleration Due to Gravity
The acceleration due to gravity, commonly denoted as \( g \), is a fundamental constant representing the acceleration experienced by an object solely under the influence of Earth's gravitational pull. On the surface of Earth, \( g \) is approximately \( 9.8 \, \text{m/s}^2 \), though it can vary slightly depending on location and altitude.
Gravity causes any falling object, such as the one in our exercise, to accelerate downward at this constant rate, which showcases uniform acceleration.
Using \( g \) in our exercise helped determine the distances that the object would fall during each half-second interval accurately.
  • It is a guiding force that simplifies understanding of motion under free fall when acting alone, as is assumed in our case.
  • Using a constant value for \( g \) ensures that our calculations for motion remain accurate across comparisons and allow for use of the standard kinematics equations.
Understanding gravity's role in motion helps not only in controlled experimental situations but also in more complex simulations of real-world motion.

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