/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 43 In the electric field shown in f... [FREE SOLUTION] | 91Ó°ÊÓ

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In the electric field shown in figure, the electric lines in the left have twice the separation as that between those on right. If the magnitude of the field at point \(A\) is \(40 \mathrm{NC}^{-1}\). The force experienced by a proton placed at point \(A\) is (a) \(6.4 \times 10^{-18} \mathrm{~N}\) (b) \(3.2 \times 10^{-15} \mathrm{~N}\) (c) \(5.0 \times 10^{-12} \mathrm{~N}\) (d) \(1.2 \times 10^{-18} \mathrm{~N}\)

Short Answer

Expert verified
The correct answer is (a) \(6.4 \times 10^{-18} \mathrm{~N}\).

Step by step solution

01

Identify the Given Data

The problem provides the electric field magnitude at point \(A\) as \(40 \mathrm{NC}^{-1}\). We need to find the force experienced by a proton placed at this point.
02

Understand the Formula for Electric Force

The force \(F\) on a charge \(q\) due to an electric field \(E\) can be calculated using the formula \(F = qE\). A proton has a charge \(q = 1.6 \times 10^{-19} \mathrm{C}\).
03

Calculate the Electric Force

Substitute the known values into the formula: \(F = (1.6 \times 10^{-19} \mathrm{C}) \times (40 \mathrm{NC}^{-1})\). This simplifies to \(F = 6.4 \times 10^{-18} \mathrm{N}\).
04

Select the Correct Answer

Compare the calculated force with the given options. The option that matches is (a) \(6.4 \times 10^{-18} \mathrm{~N}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electric Force
The electric force is a fundamental interaction that occurs between charged particles due to their electric fields. It is an essential concept in physics and plays a role in everything from the way atoms are held together to how electronic devices work. Electric force is the result of charges interacting and can be attractive or repulsive. Here, we focus on how this force acts on a charged particle within an electric field. If you have a charged object—like a proton—in an electric field, that electric field will exert a force on the charge. This electric force can be calculated using the formula
  • \(F = qE\)
where \(F\) is the force in newtons (N), \(q\) is the charge in coulombs (C), and \(E\) is the electric field strength in newtons per coulomb (\(NC^{-1}\)). Understanding how electric fields interact with charges will help you explore more complex physics problems.
Proton Charge
Every proton carries a charge, and understanding this property is crucial when calculating forces in physics. The charge of a proton is one of the fundamental constants of nature. In any physics problem involving electric forces, knowing the charge of the proton is essential. To provide a clear perspective:
  • A proton has a positive charge, denoted by \(q = 1.6 \times 10^{-19} \mathrm{C}\).
  • The positive sign indicates that it is the opposite of the negative electron charge.
This charge is a small yet powerful quantity that we use as a basis for understanding interactions of matter on the atomic scale. The reactivity of atoms and molecules, and indeed much of chemistry and biology, hinges on these electrostatic interactions.
Calculation of Force
Calculating the force that a proton experiences in an electric field requires using well-known formulas. It's straightforward with the right information and formula. When a proton is placed in an electric field, the force it experiences can be calculated by multiplying the proton's charge by the magnitude of the electric field. Using the formula
  • \(F = qE\)
  • where \(q = 1.6 \times 10^{-19} \mathrm{C}\) (charge of a proton)
  • and \(E = 40 \mathrm{NC}^{-1}\) (electric field at point \(A\))
we find the force by substituting these values. Substitution yields:
  • \(F = (1.6 \times 10^{-19} \mathrm{C}) \times (40 \mathrm{NC}^{-1})\)
  • \(F = 6.4 \times 10^{-18} \mathrm{N}\)
This result indicates the strength of the force acting on the proton at point \(A\), helping us determine how charged particles like protons behave within electric fields.

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Most popular questions from this chapter

A glass rod rubbed with silk is used to charged a gold leaf electroscope and the leaves are observed to diverse. The electroscope thin, charged is exposed to X-rays for short period. Then, (a) the leaves will diverge further (b) the leaves will melt (c) the leaves will not be affected (d) None of the above

Equipotentials at a great distance from a collection of charges whose total sum is not zero are approximately. \(\quad\) [NCERT Exemplar] (a) spheres (b) planes (c) paraboloids (d) ellipsoids

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A charge \(+q\) is fixed at each of the points \(x=x_{0}\) \(x=3 x_{0}, x=5 x_{0} \ldots \infty\), on the \(x\)-axis and a charge \(-q\) is fixed at each of the points \(x=2 x_{0}, x=4 x_{0} x=6 x_{0} \ldots \infty .\) Here, \(x_{0} \quad\) is the constant. Take the electric potential at a point due to a charge \(Q\) at a distance \(\mathrm{r}\) from it to be \(Q / 4 \pi \varepsilon_{0} r\). Then, the potential at the origin due to the above system of charges is (a) \(\frac{q}{4 \pi \varepsilon_{0} x_{0}} \log _{c} 2\) (b) \(\frac{q}{8 \pi \varepsilon_{0} x_{0}} \log _{c} 2\) (c) 0 (d) \(\infty\)

Two point charges exert on each other a force \(F\) when they are placed \(r\) distance apart in air. If they are placed \(R\) distance apart in a medium of dielectric constant \(K\), they exert the same force. The distance \(R\) equals (a) \(\frac{r}{K}\) (b) \(r \bar{K}\) (c) \(r \sqrt{K}\) (d) \(\frac{r}{\sqrt{K}}\)

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